Answer:
866.32 N
Explanation:
The diagram explains better.
Taking the total moment of forces, the sum of the clockwise moment of forces about the fulcrum must be equal to the sum of the anticlockwise moment of forces about the fulcrum:
F * (1.9 - 0.65) = 170 * 9.8 * 0.65
F * 1.25 = 1082.9
F = 1082.9/1.25
F = 866.32 N
A force of 866.32 N is needed to move the rock.
Answer:
The displacement was 320 meters.
Explanation:
Assuming projectile motion and zero initial speed (i.e., the object was dropped, not thrown down), you can calculate the displacement using the kinematic equation:
The displacement was 320 meters.
Answer:
26.8 seconds
Explanation:
To solve this problem we have to use 2 kinematics equations: *I can't use subscripts for some reason on here so I am going to use these variables:
v = final velocity
z = initial velocity
x = distance
t = time
a = acceleration
First let's find the final velocity the plane will have at the end of the runway using the first equation:
Now we can plug this into the second equation to find t:
Then using 3 significant figures we round to 26.8 seconds