All categories

2 years ago

If you run 12 m/s for 15 minutes, how far will you go?

Physics

2 answers:

worty [1.4K]2 years ago

7 0

(12 meter/second) (60 sec/minute) (15 minutes) =

(12 60 15) (meter second minute / second minute) =

10,800 meters (10.8 km, about 6.7 miles)

Note: This question doesn't represent a real-world situation. Usain Bolt's best time for 100 meters ... the current world record ... is a speed of 10.4 m/s !

vfiekz [6]2 years ago

3 0

10800 m = 10.8 km should be the answer if I am correct

You might be interested in

Which phrase best describes the side of the moon that faces Earth?

Artemon [7]

Answer:

I dont see any phrases to go with the answer was there any?

Explanation:

6 0

2 years ago

How are fission and fusion similar?

nirvana33 [79]

Answer:

Explanation:

Fusion and fission are similar in that they both release large amounts of energy. Nuclear fusion is a process in which two nuclei join to form a larger nucleus. Nuclear fission is a process in which a nucleus splits into two smaller nuclei.

8 0

2 years ago

Electromagnetic waves from the sun carry what to the earth

Rasek [7]

Answer:

Solar radiation

Explanation:

Visible light, ultraviolet light, infrared, radio waves, X-rays, and gamma rays.

7 0

2 years ago

Read 2 more answers

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin

gogolik [260]

Answer:

$7.54\cdot 10^{-7} C$

Explanation:

The capacitance of a parallel-plate capacitor is given by

$C=\frac{\epsilon_0 A}{d}$

where $\epsilon_0$ is the vacuum permittivity, A is the surface area of the plates, d their separation.

We also know the following relationship

$C=\frac{Q}{V}$

where Q is the charge stored on the capacitor and V the potential difference between the plates.

Combining the two equations,

$\frac{\epsilon_0 A}{d}=\frac{Q}{V}$

We also know that for a uniform electric field (such as the one between the plates of a parallel-plate capacitor), we have

$V= Ed$

where E is the magnitude of the electric field. Substituting into the previous equation and re-arranging it,

$\frac{\epsilon_0 A}{d}=\frac{Q}{Ed}\\Q=\frac{\epsilon_0 A E d}{d}=\epsilon_0 A E$

For the capacitor in the problem:

$A=\pi r^2 = \pi (\frac{d}{2})^2 = \pi (\frac{0.19 m}{2})^2=0.0284 m^2$ is the area of the plates

$E=3\cdot 10^6 N/C$ is the maximum electric field before a spark is produced

Solving for Q, we find the maximum charge that can be added before that occurs:

$Q=(8.85\cdot 10^{-12})(0.0284)(3\cdot 10^6)=7.54\cdot 10^{-7} C$

3 0

3 years ago

What is the definition of a electromagnet?

nikdorinn [45]

Hello there,
<span>It is a soft metal core made into a magnet by the passage of electric current through a coil surrounding it.

Hope this helps :))

~Top
</span>

7 0

2 years ago