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topjm [15]
3 years ago
11

Can charging by friction only occur in solids

Physics
1 answer:
Sonja [21]3 years ago
6 0
Yes you are right cuz charging by friction cant be done in fluids( liquid and gas)
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Which is the correct scientific notation for 724,000,000,000?
NikAS [45]

Answer:

Explanation:

scientific notation for 724,000,000,000 is

7.24*10^11

5 0
4 years ago
During each heartbeat, about 80 g of blood is pumped into the aorta inapproximately 0.2 s. During this time, the blood is accele
taurus [48]

Answer:

Work is done by the heart on the blood during this time is 0.04 J

Explanation:

Given :

Mass of blood pumped, m = 80 g = 0.08 kg

Initial speed of the blood, u = 0 m/s

Final speed of the blood, v = 1 m/s

Initial kinetic energy of blood is determine by the relation:

E_{1}=\frac{1}{2} m u^{2}

Final kinetic energy of blood is determine by the relation:

E_{2}=\frac{1}{2} m v^{2}

Applying work-energy theorem,

Work done = Change in kinetic energy

W = E₂ - E₁

W=\frac{1}{2} m (v^{2}-u^{2})

Substitute the suitable values in the above equation.

W=\frac{1}{2}\times0.08\times (1^{2}-0^{2})

W = 0.04 J

6 0
3 years ago
A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A horizontal force of 2.5 N is applied o
Masja [62]

Answers is  F=7.84 N

Friction force resists the effect of horizontal force and trying to approch to a limiting force.

we have formula for limiting friction force between block and floor

               F=Ц N

where N=mg

putting values we get answer.

Download pdf
3 0
3 years ago
Which statements best describe displacement? Check all that apply.
xxMikexx [17]

Answer:

the last one, the third one, and the first one.

8 0
3 years ago
Read 2 more answers
A 1500 kg car, initially traveling at 22.0 m/s, hits its brakes and skids to a stop. Determine the work done by friction.
Sedbober [7]

Answer:

<em>The work done by the car is 363 kJ</em>

Explanation:

Work : Work is said to be done when a Force moves an object through a certain distance. Work and Energy are interchangeable because they have the same unit. The unit of work is Joules (J).

Mathematically work done can be expressed as,

E = W = 1/2mv²

W =  1/2mv²................................ Equation 1

Where E = Energy, W = work done, m = mass of the car, v = velocity of the car

<em>Given: m=1500 kg, v=22 m/s</em>

<em>Substituting these values into equation 1</em>

<em>W = 1/2(1500)(22)²</em>

<em>W = 750 × 484</em>

<em>W = 363000 J</em>

<em>W = 363 kJ</em>

<em>Thus the work done by the car is 363 kJ</em>

8 0
3 years ago
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