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Vikki [24]
3 years ago
5

Which phrases describe NASA's goals in the coming years? Check all that apply.

Physics
2 answers:
Butoxors [25]3 years ago
4 0

Answer:

true, false, true, true, false

Explanation:

I did the test

Serggg [28]3 years ago
3 0

Answer:

1, 3 and 4

Explanation:

Did the test and saw the answers.

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WHAT ARE THE NECESSARY CONDITIONS TO CREATE A WAVE?
never [62]
There are no necessary conditions there’s always waves the ocean is never still or if your talking about a lake you need movement
3 0
3 years ago
A stone is launched from the ground, at a 70° angle, with an initial velocity of 120 m/s.
zavuch27 [327]
<span>A) x = 41t
    The classic equation for distance is velocity multiplied by time. And unfortunately, all of your available options have the form of that equation. In fact, the only difference between any of the equations is what looks to be velocity. And in order to solve the problem initially, you need to divide the velocity vector into a vertical velocity vector and a horizontal velocity vector. And the horizontal velocity vector is simply the cosine of the angle multiplied by the total velocity. So H = 120*cos(70) = 120*0.34202 = 41.04242 So the horizontal velocity is about 41 m/s. Looking at the available options, only "A" even comes close.</span>
3 0
3 years ago
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Calculate the total surface area of cylinder whose base radius 2cm and height is 10cm​
murzikaleks [220]

Answer:

Answer :-  150.79cm2

Explanation:

                                               A=2πrh+2πr2

                                                 2·π·2·10+2·π·22

                                                    150.79645cm²

5 0
3 years ago
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The acceleration of an object depends upon
aalyn [17]
Its mass and net force acting on it
4 0
3 years ago
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To determine the height of a bridge above the water, a person drops a stone and measures the time it takes for it to hit the wat
myrzilka [38]

The stone will take 2.89 seconds to hit the water.

The time required by the stone to hit the water is calculated by the second equaiton of motion

s=ut+\frac{1}{2}gt^2

41=0×t+\frac{1}{2}×9.81×t²

t=2.89 seconds

8 0
3 years ago
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