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3 years ago

what was the temperature change in Celsius degree if it is changed from 44 degree fahrenheit to -56 degree fahrenheit

Physics

1 answer:

wel3 years ago

5 0

Answer:

-11.11 degree Celsius

Explanation:

The change was 44 degree fanhereit

To 56 degree fanhereit

Therefore the temperature range can be calculated as follows

56-44

= 12 degree fanhereit to Celsius

= 12-32×5/9

= -20×5/9

= 100/9

= -11.11 degree Celsius

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Newton’s second law of motion states that an object with a heavier mass will have more acceleration than an object with a smalle

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If Vx = 7.00 units and Vy = -7.60 units, determine the magnitude of V⃗ .

Juliette [100K]

|V| = 10.33 units and the direction θ = -47.35° or 312.65°.

Given the x and y components of a vector, we can calculate the magnitude and direction from these components.

Applying the Pythagorean theorem we have that the magnitude of the vector is:

|V| = $\sqrt{Vx^{2}+Vy^{2} }$

|V| = $\sqrt{(7.00units)^{2}+(-7.60units)^{2}} = \sqrt{106units^{2}} = 10.33units$

The expression for the direction of a vector comes from the definition of the tangent of an angle:

tan θ = $\frac{Vy}{Vx}$ ------> θ = arc tan $\frac{Vy}{Vx}$

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6 0

3 years ago

Xenon has an enthalpy of vaporization of 12.6 kJ/mol and a vapor pressure of 1.00 atm at –108.0 °C. What is the vapor pressure o

earnstyle [38]

Answer:

P₁ = 0.0562 atm

Explanation:

Using the Clausius-Clapeyon equation

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁) ------ (eqn 1)

Step 1: From the question given, we state out the parameters given

P₁ = ? T₁ = -148.0⁰C

P₂ = 1atm T₂ = -108.0⁰C

ΔHvap = 12.6kJ/mol R = 8.314J/K.mol

Step 2: Do conversions where necessary for unit consistency since our R value is in J/K.mol

a) convert ⁰C to K

1K = ⁰C + 273.15

T₁ = -148.0⁰C => -148.0⁰C + 273.15

T₁ = 125.15K

T₂ = -108.0⁰C => -108.0⁰C + 273.15

T₂ = 166.15K

b) convert kJ/mol to Joules

ΔHvap = 12.6kJ/mol = 12600Joules

substituting parameters into eqn 1

ln (P₁ / P₂) = ΔHvap/R (1/T₂ - 1/T₁)

ln (P₁/1atm) = 12600J / 8.314 (1/166.15 - 1/125.15)

= 1515.51 (0.0060 - 0.0079)

= 1515.51(-0.0019)

ln (P₁/1atm) = -2.8794

taking exponential of both sides to get rid of the natural log

P₁ = e^ -2.8794

P₁ = 0.05616 atm

P₁ = 0.0562atm

Key Words

1) Clausius-Clapeyon: shows the relationship between pressure and temperature and it is used to estimate the vapour of a solution at a different temperature

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13.00 cm + 2.56 mm + 0.0047= cm? Solve problem with correct number of significant digits

Drupady [299]

The answer is 13.2607 cm

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what was the temperature change in Celsius degree if it is changed from 44 degree fahrenheit to -56 degree fahrenheit​

what was the temperature change in Celsius degree if it is changed from 44 degree fahrenheit to -56 degree fahrenheit