All categories

3 years ago

Convert 2.55 days to seconds.

Chemistry

1 answer:

Temka [501]3 years ago

4 0

Answer:

2.55 minutes = 153 seconds

Explanation:

You might be interested in

It is desired that an acetic acid sodium acetate buffered solution have a pH of 5.27. You have a solution that has an acetic aci

SVETLANKA909090 [29]

Answer:

0.034 M is the molarity of sodium acetate needed.

Explanation:

The pH of the buffer solution is calculated by the Henderson-Hasselbalch equation:

$pH = pK_a + \log \frac{[A^-]}{[HA]}$

Where:

pK_a= Negative logarithm of the dissociation constant of a weak acid

$[Ac^-]$ = Concentration of the conjugate base

[HA] = Concentration of the weak acid

According to the question:

$HAc(aq)\rightleftharpoons Ac^-(aq)+H^+(aq)$

The desired pH of the buffer solution = pH = 5.27

The pKa of acetic acid = 4.74

The molarity of acetic acid solution = [HAc] = 0.01 M

The molarity of acetate ion = $[Ac^-] = ?$

Using Henderson-Hasselbalch equation:

$5.27= 4.74 + \log \frac{[Ac^-]}{[0.01 M]}$

$[Ac^-]=0.0339 M\approx 0.034M$

Sodium acetate dissociates into sodium ions and acetate ions when dissolved in water.

$NaAc(aq)\rightarrow Na^+(aq)+Ac^-(aq)\\$

$[Ac^-]=[Na^+]=[NaAc]= 0.034M$

0.034 M is the molarity of sodium acetate needed.

3 0

3 years ago

How many moles of potassium K will react with 3 moles of sulfur S?

IceJOKER [234]

Explanation:

KOH + 2H2SO4 ======> 2K2SO4 + H20

$3 \: mol \: s \: \times \: \frac{4 \: mol \: k}{2 \: mol \: s} \: = 12 \: mol \: k$

7 0

3 years ago

P−aminobenzenesulfonic acid (sulfanilic acid) is normally written in the form shown but its zwitterionic form is more stable. wr

polet [3.4K]

Zwitterion is an ion consists of equal positive and negative charges on the same molecule which make it more stable and has high melting point
p-aminobenzene sulfonic acid contains both acidic (-SO₃H) and basic groups (NH₂), the acidic group will lose one proton to give (-SO₃⁻) and the basic group will gain this proton to give (-NH₃⁺)
The structure is:

3 0

3 years ago

Calculate the mass of water formed when 4g of methane is burnt in excess oxygen

wariber [46]

Answer:

Mass of water formed: 9g

Explanation:

Hope it helps you!

6 0

2 years ago

0.467 mol NaCl are needed to

Alisiya [41]

Answer:

27.4 gram is the solution it's simple dude...

Explanation:

don't be afraid of huge question they confuse you you need not to be confused

now see simple solution

molality is denoted by m

m= moles of solute / mass of solvent in kg.

i hope your know the meaning of solute and solvent....

so moles are given 0.467

and molar mass is given 58.44

so just take out the gram means

by applying formula

58.44×0.467

it will give 27.4 grams simple.....

8 0

2 years ago