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Liula [17]
3 years ago
13

How could you separate a mixture of rocks and sand

Chemistry
1 answer:
Assoli18 [71]3 years ago
7 0
Sedimentation and decantation




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Use the ball and stick models above. If you had a gram of water and a gram of
Sladkaya [172]

Answer:

When the weather is nice, many people begin to work on their yards and homes. For many projects, sand is needed as a foundation for a walk or to add to other materials. You could order up twenty million grains of sand and have people really stare at you. You could order by the pound, but that takes a lot of time weighing out. The best bet is to order by the yard, meaning a cubic yard. The loader can easily scoop up what you need and put it directly in your truck.

Avogadro’s Number

It certainly is easy to count bananas or to count elephants (as long as you stay out of their way). However, you would be counting grains of sugar from your sugar canister for a long, long time. Atoms and molecules are extremely small – far, far smaller than grains of sugar. Counting atoms or molecules is not only unwise, it is absolutely impossible. One drop of water contains about 10 22 molecules of water. If you counted 10 molecules every second for 50 years without stopping you would have counted only 1.6 × 10 10 molecules. Put another way, at that counting rate, it would take you over 30 trillion years to count the water molecules in one tiny drop.

Explanation:

6 0
3 years ago
The structural form of the element Ge closely resembles the structure of A. C (diamond) B. N (diatomic) C. As (tetrahedral) D. S
Ksivusya [100]

The structural form of the element Ge closely resembles the structure of C (diamond).

Diamond is composed of a lattice structure in which atoms of carbon are held together in a face centered cubic lattice.

Germanium, an element in the same group as carbon also forms a face centered cubic lattice that is very similar to that of diamond.

Hence, the  structural form of the element Ge closely resembles the structure of C (diamond).

Learn more: brainly.com/question/14578576

6 0
3 years ago
Please match the orbital type with the correct number of orbitals
saul85 [17]
Hi there!

p = e-3
s = f-1
f = i-7
d = g-5

Hope that helps!
Brady
7 0
3 years ago
Assuming it behaves as an ideal gas, calculate the density of sulfur dioxide, so2, at stp.
Arisa [49]
Hello!

At Standard Pressure and Temperature, an ideal gas has a molar density of  0,04464 mol/L.

So, we need to apply a simple conversion factor to calculate the density of Sulfur Dioxide using the molar mass of Sulfur Dioxide.

\frac{0,04464 mol SO_2}{1 L SO_2}* \frac{64,066 g SO_2}{1 mol SO_2}=2,8599 g/L

So, the Density of Sulfur Dioxide (SO₂) at STP is 2,8599 g/L

Have a nice day!


6 0
3 years ago
Read 2 more answers
A student calculated the density of a sample of graphite to be 2.3 g/cm3. Show a numerical setup for calculating the student’s p
LUCKY_DIMON [66]

Answer:

Percent error = 1.5%

Explanation:

Given data:

Measured value of density of graphite = 2.3 g/cm³

Percent error = ?

Solution:

Formula:

Percent error = [Measured value - Actual value / actual value] × 100

Actual/accepted value of density of graphite = 2.266 g/cm³

Now we will put the values:

Percent error = [2.3 g/cm³ - 2.266 g/cm³ / 2.266 g/cm³] × 100

Percent error = [0.034 g/cm³ / 2.266 g/cm³] × 100

Percent error = 0.015  × 100

Percent error = 1.5%

8 0
3 years ago
Read 2 more answers
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