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otez555 [7]
3 years ago
6

Vector B has x y, and z components of 8.8,

Physics
1 answer:
Ostrovityanka [42]3 years ago
3 0

Answer: 14.122 units

Explanation:

We have the following vector:

\vec{V}=(x,y,z)=(8.8, 7.4, 8.2)

If we want to find its magnitude we have to use the following formula:

V=\sqrt{x^{2}+y^{2}+z^{2}}

V=\sqrt{(8.8units)^{2}+(7.4units)^{2}+(8.2 units)^{2}}

V=14.122 units  This is the magnitude of vector \vec{V}

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A toy helicopter takes off and moves 6 m up and then 1 m back down. What
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the answer is 5 m up AKA "B"

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Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. Suppose the screen is a distance
scZoUnD [109]

Answer:

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

x_{1}=\dfrac{\lambda D}{2d}

Second minima from center

x_{2}=\dfrac{3\lambda D}{2d}

The distance between the places where the intensity is zero due to the double slit effect

\Delta x_{d}=x_{2}-x_{1}

\Delta x_{d}=\dfrac{3\lambda D}{2d}-\dfrac{\lambda D}{2d}

\Delta x_{d}=\dfrac{\lambda D}{d}

Put the value into the formula

\Delta x_{d}=\dfrac{600\times10^{-9}\times1}{0.04\times10^{-3}}

\Delta x_{d}=0.015 =15\times10^{-3}\ m

\Delta x_{d}=15\ mm

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

8 0
3 years ago
Sound waves can be modeled by the equation of the form y=20sin(3t+theta). Determine what type of interference results when sound
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3 years ago
How can you determine the number of valence electrons in atom without drawing a Bohr model?
grigory [225]
Using your periodic table if you look at it 3-11 are tansition metals so the horizontal Group Number will help if the group number has to digits just remove the one so if it were to be 13, the valence would be 3, if it were 14 the valence would be ,4 if it were 15, the valence would be 5, if it were 16 the valence would be 6, if it were 17 the valence would be 7 if it were group 18 the valence would be 8 so if anymore help needed to explain hit me up
5 0
3 years ago
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The count rate of a radioactive source decreases from 1600 counts per minute to 400 counts per minute in 12 hours. What is the h
kirill115 [55]

Answer:

t_{1/2}=6 h

Explanation:

Let's use the decay equation.

A=A_{0}e^{-\lambda t}

Where:

  • A is the activity at t time
  • A₀ is the initial activity
  • λ is the decay constant

We know that \lambda=\frac{ln(2)}{t_{1/2}}

So we have:

\lambda=\frac{ln(A/A_{0})}{t}

\frac{ln(2)}{t_{1/2}}=\frac{ln(A/A_{0})}{t}

t_{1/2}=\frac{t*ln(2)}{ln(A/A_{0})}

t_{1/2}=6 h

Therefore, the half-life of the source is 6 hours.

I hope it helps you!

4 0
3 years ago
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