Answer:
11.94 grams of carbon dioxide were originally present.
19.94 grams of krypton can you recover.
Explanation:
Mass of carbon dioxide gas = x
Mass of krypton gas = y
x + y = 31.7 g
Moles of carbon dioxide gas = 
Moles of krypton gas = 
Mole fraction of krpton =
Total pressure of the mixture = P = 0.665 atm
Partial pressure of carbon dioxide gas = p
Partial pressure of krypton gas before removal of carbon dioxide gas = p'
Partial pressure of krypton gas after removal of carbon dioxide gas = p'' = 0.309 atm
p' = p'' = 0.309 atm
0.665 atm = p + 0.309 atm
p = 0.665 atm - 0.306 atm = 0.359 atm
Partial pressure of krypton can also be given by :
..[2]
Solving [1] and [2]:
x = 11.94 g
y = 19.76 g
11.94 grams of carbon dioxide were originally present.
19.94 grams of krypton can you recover.
P1V1 = P2V2
Convert 248mm Hg to atm
248/760 = 0.326 atm
(0.326 atm • 1.05L) / 3.98L = 0.0861 atm
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Draw a reasonable Lewis structure for the substance.
Step 2: Identify each bond as either polar or nonpolar. (If the difference in electronegativity for the atoms in a bond is greater than 0.4, we consider the bond polar. If the difference in electronegativity is less than 0.4, the bond is essentially nonpolar.)
If there are no polar bonds, the molecule is nonpolar.
If the molecule has polar bonds, move on to Step 3.
Step 3: If there is only one central atom, examine the electron groups around it.
If there are no lone pairs on the central atom, and if all the bonds to the central atom are the same, the molecule is nonpolar. (This shortcut is described more fully in the Example that follows.)
If the central atom has at least one polar bond and if the groups bonded to the central atom are not all identical, the molecule is probably polar. Move on to Step 4.
Step 4: Draw a geometric sketch of the molecule.
Step 5: Determine the symmetry of the molecule using the following steps.
Describe the polar bonds with arrows pointing toward the more electronegative element. Use the length of the arrow to show the relative polarities of the different bonds. (A greater difference in electronegativity suggests a more polar bond, which is described with a longer arrow.)
Decide whether the arrangement of arrows is symmetrical or asymmetrical
If the arrangement is symmetrical and the arrows are of equal length, the molecule is nonpolar.
If the arrows are of different lengths, and if they do not balance each other, the molecule is polar.
If the arrangement is asymmetrical, the molecule is polar.
