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adelina 88 [10]
3 years ago
10

Water flows through a multisectional pipe placed horizontally on the ground. The velocity is 3.0 m/s at the entrance and 2.1 m/s

at the exit. What is the pressure difference between these two points? Neglect friction.
Physics
1 answer:
Stolb23 [73]3 years ago
5 0

Answer:

P_1 - P_2 = 2295 pascal

Explanation:

As we know by Bernoulli's principle

P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2

P_1 - P_2 = \frac{1}{2}\rho v_2^2 - \frac{1}{2} \rho v_1^2

here we know that

\rho = 1000 kg/m^3

also we know that

v_1 = 2.1 m/s

v_2 = 3 m/s

now we have

P_1 - P_2 = \frac{1}{2}(1000)(3.0^2 - 2.1^2)

P_1 - P_2 = 2295 pascal

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