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IRISSAK [1]
3 years ago
7

The voltage across a conductor is increasing at a rate of 2 volts/min and the resistance is decreasing at a rate of 1 ohm/min. U

se I = E/R and the Chain Rule to find the rate at which the current passing through the conductor is changing when R = 20 ohms and E = 70 volts.
Physics
1 answer:
Lelechka [254]3 years ago
3 0

Answer:

3.5 amperes

Explanation:

I = E/R

I = ?

E = 70volts

R = 20 Ohms

Therefore , I = 70/20

= 3.5 amperes

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An iron wire has a cross-sectional area equal to 5.00×10⁻⁶ m² . Carry out the following steps to determine the drift speed of th
Doss [256]
  1. In mass, there are 55.85 × 10⁻³ kg/mol in in 1 mole of iron.
  2. The molar density of iron is equal to 1.41 × 10⁵ mol/m³.
  3. The density of iron atoms is equal to 8.49 × 10²⁸ atoms/m³.
  4. The number density of conduction electrons is equal to 1.70 × 10²⁹ conduction electrons/m³.
  5. The drift speed of conduction electrons is equal to 2.21 × 10⁻⁴ m/s.

<h3>How to calculate the drift speed of the conduction electrons?</h3>

Mathematically, the drift speed of the conduction electrons can be calculated by using this formula:

V = (m × σ × V)/ρ × e × f × l)

V = I/(n × A × Q)

Where:

  • U represents the drift speed of the conduction electrons, in m/s.
  • m represents the molecular mass of the metal, in kg.
  • e represents the elementary charge, in C.
  • f represents the number of free electrons per atom.
  • σ represents the electric conductivity of the medium at a particular temperature in S/m.
  • ρ represents the density of the conductor, in kg/m³.
  • ℓ represents the length of the conductor, in m.
  • ΔV represents the voltage applied or potential difference across the conductor in V.

<h3>How many kilograms are there in 1 mole of iron? </h3>

Molar mass of iron = 55.85 g/mol.

In Kilograms, we have:

Mass = 55.85 × 1/1000

Mass = 55.85 × 10⁻³ kg/mol.

For the molar density of iron, we have:

Molar density = density/molar mass

Molar density = 7874/0.056

Molar density = 1.41 × 10⁵ mol/m³.

For the density of iron atoms, we have:

Density of iron atoms = Avogadro's constant × molar density

Density of iron atoms = 6.023 × 10²³ × 1.406 × 10⁵

Density of iron atoms = 8.49 × 10²⁸ atoms/m³.

For the number density of conduction electrons, we have:

Fe ---> Fe²⁺ + 2e⁻

Number density of conduction electrons = 2 conduction electrons/1 atom of iron

Number density of conduction electrons = 2 × 8.49 × 10²⁸

Number density of conduction electrons = 1.70 × 10²⁹ conduction electrons/m³.

For the drift speed of conduction electrons, we have:

V = I/(n × A × Q)

V = 30/(1.70 × 10²⁹ × 1.602 × 10⁻¹⁹ × 5 × 10⁻⁶)

Drift speed, V = 2.21 × 10⁻⁴ m/s.

Read more on drift speed here: brainly.com/question/15219891

#SPJ4

Complete Question:

An iron wire has a cross-sectional area of 5.00 x 10-6 m2. Carry out steps (a) through (e) to compute the drift speed of the conduction electrons in the wire.

(a) How many kilograms are there in 1 mole of iron?

(b) Starting with the density of iron and the result of part (a), compute the molar density of iron (the number of moles of iron per cubic meter).

(c) Calculate the number density of iron atoms using Avogadro’s number.

(d) Obtain the number density of conduction electrons given that there are two conduction electrons per iron atom.

(e) If the wire carries a current of 30.0 A, calculate the drift speed of conduction electrons.

4 0
2 years ago
Confused..................
svlad2 [7]
1. Dump the container out.
2. Sift the large items out until the sugar and gravel is by itself.
3. Continue separating the other items.
3 0
3 years ago
A 1500 kg car carrying four 90 kg people travels over a "washboard" dirt road with corrugations 3.7 m apart. The car bounces wit
umka21 [38]

Answer:

Car body rise on its suspension by 0.0309 m

Explanation:

We have given mass of the car m = 1500 kg

Mass of each person = 90 kg

Speed of the car v=20km/hr=20\times \frac{5}{18}=5.555m/sec

Distance traveled by car d = 3.7 m

So time period  T=\frac{distance}{speed}=\frac{4}{5.55}=0.72sec

Frequency f=\frac{1}{T}=\frac{1}{0.72}=1.388Hz

Angular frequency is \omega =2\pi f=2\times 3.14\times 1.388=8.722rad/sec

Angular frequency is equal to \omega =\sqrt{\frac{k}{m}}

8.722 =\sqrt{\frac{k}{1500}}

k = 114109.92 N/m

Now weight of total persons will be equal to spring force

4mg=kx

4\times 90\times 9.8=114109.92\times x

x = 0.0309 m

7 0
3 years ago
Calculate the density of gold if 96500kg mass of gold is adjusted in the volume of 5m cube​
PSYCHO15rus [73]

Answer:

96500÷5=19300

Explanation:

96500÷5=19300

6 0
3 years ago
A charged particle moving in a magnetic field will be deflected in a direction ____________________ to the magnetic field
fenix001 [56]
<span>A charged particle moving in a magnetic field will be deflected in a direction <u>perpendicular </u>to the magnetic field. This is the vector equation: </span><span>F = m a = q v x B. </span>
4 0
3 years ago
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