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IRISSAK [1]
3 years ago
7

The voltage across a conductor is increasing at a rate of 2 volts/min and the resistance is decreasing at a rate of 1 ohm/min. U

se I = E/R and the Chain Rule to find the rate at which the current passing through the conductor is changing when R = 20 ohms and E = 70 volts.
Physics
1 answer:
Lelechka [254]3 years ago
3 0

Answer:

3.5 amperes

Explanation:

I = E/R

I = ?

E = 70volts

R = 20 Ohms

Therefore , I = 70/20

= 3.5 amperes

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One of the element carbon combines with one of the element oxygen to form one of the compound carbon dioxide.
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False. C + O --> CO not CO2. Carbonmonoxide
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3 years ago
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If the resultant force acting on a 2.0 kg object is equal to (3.0î + 4.0ĵ) N, what is the change in kinetic energy as the object
12345 [234]

Answer:

ΔK = 24 joules.

Explanation:

ΔK = Work done on the object

Work is equal to the dot product of force supplied and the displacement of the object.

W = F * Δs

Δs can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δs = (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).

This gives us

W = < 3, 4 > * < 4, 3 > = (3*4)+(4*3) = 24 J

3 0
1 year ago
If a truck has the mass of 2,000 kilometres and a velocity of 35 m/s, what is the momentum
alexira [117]

Answer:

<h2>70,000 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 2000 × 35

We have the final answer as

<h3>70,000 kg.m/s</h3>

Hope this helps you

5 0
2 years ago
THE ANSWER!!! Please
Anuta_ua [19.1K]

Answer:

I think -7 N. Netforce is 3N-10N= -7N

Explanation:

5 0
2 years ago
A 35 g steel ball is held by a ceiling-mounted electromagnet 3.8 m above the floor. A compressed-air cannon sits on the floor, 4
n200080 [17]

Answer:

Explanation:

Let v is the launch speed of the plastic ball and the angle of projection is θ.

So, in horizontal direction

v Cosθ x t = 4.8 .... (1)

In th evertical direction

1.4 = v Sin θ x t - 0.5 gt²     .... (2)

As , v Sin θ x t = 3.8      .... (3) , put in equation (2)

1.4 = 3.8 - 4.9 t²

t = 0.7 s

Put in (1) and (3)

v Cosθ x 0.7  = 4.8

v Cosθ = 6.86

and v Sinθ x 0.7 = 3.8

v Sinθ = 5.43

Now

v^{2}\left ( Sin^{2}\theta +Cos^{2}\theta  \right )=5.43^{2}+6.86^{2}

v = 8.75 m/s

3 0
3 years ago
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