The average time that it takes for the car to travel the first 0.25m is 2.23 s
The average time that it takes for the car to travel the first 0.25 m is given by:
The average time to travel just between 0.25 m and 0.50 m is 0.90 s
First of all, we need to calculate the time the car takes in each trial to travel between 0.25 m and 0.50 m:
Then, the average time can be calculated as
Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s
The velocity of the car while travelling the second 0.25 m section is equal to the distance covered (0.25 m) divided by the average time (0.90 s):
In this graph, what is the displacement of the particle in the last two seconds?of the particle in the last two seconds?
<span>0.2 meters
2 meters
4 meters
6 meters</span>
In this graph, the displacement of the particle in the last two seconds is 2 meters.
Force = (mass) x (acceleration)
Mass = (force) / (acceleration)
There was 150N of force in one direction and 100N of 'force' in
the other direction. The net force on the object was (150 - 100) = 50N .
Acceleration = (change in speed) / (time for the change)
= (10 m/s) / (5s) = 2 m/s²
Mass = (net force) / (acceleration) = (50 N) / (2 m/s²) = 25 kilograms
Explanation:
Introduction to the quantum mechanical model of the atom: Thinking about electrons as probabilistic matter waves using the de Broglie wavelength, the Schrödinger equation, and the Heisenberg uncertainty principle. Electron spin and the Stern-Gerlach experiment.
Answer:
The sun's mass moved toward the outer edge of it
Explanation:
