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3 years ago

In which species does nitrogen have an oxidation number of zero?

1 answer:

4 0

The most common species of nitrogen in which its oxidation state is zero is the diatomic nitrogen ( $N_{2}$ ). This is because the oxidation number of pure elements (whether alone as an atom or combined with other atoms of the same element such as the diatomic nitrogen) is always zero.

In addition to diatomic nitrogen, there are diazonium ( $R-N_{2}^{+}$ ) compounds where nitrogen has an oxidation number of zero.

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11.23 mm = ____ m 1,123 m 0.01123 m 0.1123 m 11,230 m

kaheart [24]

For every meter, the equivalent measurements is 1000 millimeters. Hence in the problem where the number of millimeters is given, we divide the number by 1000 to get the number of meters. The answer here is 0.01123 m.

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3 years ago

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Which of these factors should remain constant in a simulation of natural

musickatia [10]

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2 years ago

Which of the following describes a condition in which an individual would not hear an echo?

egoroff_w [7]

The correct answer is D.

Echo refers to the sound that is heard when a sound wave is reflected back from a surface. An echo sound is made when a sound wave traveled through the air, hit a hard surface and get reflected back. Generally, hard surfaces reflect sound wave while soft surfaces absorb sound waves. Reflected sound waves are used in application of some devices that are used in range and direction finding.

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3 years ago

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Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th

artcher [175]

Answer:

The equilibrium constant is:

$k_c=0.0030M^{-2}$

Explanation:

The correct equation is:

N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

$k_c=\dfrac{[NH_3]^2}{[N_2]\cdot [H_2]^3}$

Substituting:

$k_c=\dfrac{(0.105M)^2}{(1.1M)\cdot (1.50M)^3}$

$k_c=0.0030M^{-2}$

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3 years ago

Explain the need of the term avarage atomic mass

vodomira [7]

Answer:

The average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance (the decimal associated with percent of atoms of that element that are of a given isotopе). An element does not have an absolute atomic mass.

Hope this helps :)

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3 years ago