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3 years ago

11

How does the light source readout differ from the x-ray readout in the gizmo??

1 answer:

Nuetrik [128]3 years ago

8 0

X-rays differ from the light source readout in terms of the intensity and the possible damage that can be obtained from the two radiation types. The light source readout is more damaging than the X-rays readout in the gizmo. Therefore, precaution is required when handling the light source readout in the gizmo.

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Write a balanced equation for the combustion of hexane, C6H14 (l)

stich3 [128]

The combustion of hexane (C6H14), a component of gasoline, is represented by the balanced chemical equation: 2 C6H14(l) + 19 O2(g) " 12 CO2(g) + 14 H2O(g). If 1.0 mole of hexane undergoescombustion, moles of O2 are required.

8 0

3 years ago

How many moles of copper are present in 75.0g Cu? Show your complete calculation and give the answer in the correct number of si

velikii [3]

Answer:

The answer to your question is 1.2 moles of copper

Explanation:

Data

mass of copper = 75 g

moles = ?

Process

1.- Look in the periodic table for the atomic mass of copper.

Atomic mass = 63.55 g/mol

2.- Use proportions to determine the moles of copper in 75 g

63.55 g of copper -------------------- 1 mol

75 g of copper -------------------- x

Use cross multiplication

x = (75 x 1) / 63.55

x = 75 / 63.55

x = 1.18 moles ≈ 1.2 moles of copper

3 0

4 years ago

Read 2 more answers

The fire department needs information on friction losses occurring between a water main and an open fire hydrant. At maximum mai

lisov135 [29]

Explanation:

The given data is as follows.

$P_{1}$ = 85 psig, $P_{2}$ = $P_{atm}$ = 15 psia

Q = 1620 gpm, d = 2.5 inch, l = 8 ft = 2.4384 m

According to Darey-Weisbach equation,

$h_{l} = \frac{4fl \nu^{2}}{2gD}$ ......... (1)

Value of 'f' will be decided on the basis of Reynold number.

As, it is known that $R_{l} = \frac{\rho \nu d}{\mu}$

where, $\mu_{water}$ = $10^{-3}$ kg/ms

As it is known that 1 gpm = $\frac{1}{3.67} m^{3}/hr$

So, $1 m^{3}/hr$ = 3.67 gpm

Therefore, Q = $1620 \times \frac{1}{3.67}$

= $441.4168 m^{3}/hr$

= 0.1226 $m^{3}/s$

In, 1 inch = 2.54 cm = 0.0254 m

Therefore, d = 2.5 \times 0.0254 = 0.0635 m

V = $\frac{Q}{\frac{\pi}{4}d^{2}}$

= $\frac{0.1226}{0.785 \times (0.0635)^{2}}$

= 38.73 m/s

Hence, we will calculate Reynold number as follows.

$R_{l}$ = $\frac{1000 \times 38.73 \times 0.0635}{10^{-3}}$

= 2459355

As $R_{l}$ > 2000 then, it means that flow is turbulent.

As, f = 0.079 $R^{-0.25}_{l}$

= 0.001994

Putting all the values into equation (1) formula as follows.

$h_{l} = \frac{4fl \nu^{2}}{2gD}$

= $\frac{4 \times 0.001994 \times 2.4384 \times (38.73)^{2}}{2 \times 9.81 \times 0.0635}$

= $1.04069 \times 10^{5} m$

Thus, we can conclude that friction loss from the main to the discharge point is $1.04069 \times 10^{5} m$ .

4 0

3 years ago

How many dollars are in 140 dimes? using dimensional analysis

Nutka1998 [239]

Answer:

1 dollar

Explanation:

3 0

1 year ago

What does diatomic mean?

Tanya [424]

Answer: [A]: "<span><span>two atoms, both the same element, bonded together</span>".
</span><span>_____________________________________________________________</span>

4 0

4 years ago