The burning of glucose in presence of oxygen is called as combustion
The balanced reaction is
C6H12O6 + 6O2 ---> 6CO2 + 6H2O
Thus for each mole of glucose we need six moles of oxygen molecules
molar mass of glucose is 180g / mole
The moles of glucose present = mass / molar mass = 180 / 180 = 1 mole
The moles of oxygen present = mass / molar mass = 192 / 32 = 6 moles
Thus the reaction will go to completion and one mole of glucose will react with six moles of O2 to give six moles of CO2 and six moles of H2O
Mass of CO2 produced = moles X molar mass = 6 x 44 = 264 g
Mass of H2O produced = moles X molar mass = 6 x 18 = 108 g
Answer:
No because it is stayed that way and you can't define them differently.
Answer:
The six member ring and the position of the -OH group on the carbon (#4) identifies glucose from the -OH on C # 4 in a down projection in the Haworth structure). Fructose is recognized by having a five member ring and having six carbons, a hexose.
Mass of sodium thiosulfate 
is 110. g
Volume of the solution is 350. mL
Calculating the moles of sodium thiosulfate:
= 0.696 mol
Converting the volume of solution to L:
Finding out the concentration of solution in molarity:
