3 years ago

How does the light source readout differ from the x-ray readout in the gizmo??

1 answer:

8 0

X-rays differ from the light source readout in terms of the intensity and the possible damage that can be obtained from the two radiation types. The light source readout is more damaging than the X-rays readout in the gizmo. Therefore, precaution is required when handling the light source readout in the gizmo.

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The specific heat of a certain type of cooking oil is 1.75 j/(g·°c). how much heat energy is needed to raise the temperature of

love history [14]

The energy needed to raise the temperature of 2.83 kg of the oil from 23 to 191 is calculated using Mc delta T formula

M= mass ( 2.83 Kg to grams = 2.83 x1000= 2830 grams)
C= specific heat capacity = 1.75 j/g/c
delta T= change in temperature = 191- 23 = 168 c

heat energy = 1.75 j/g/c x 2830 g x 168 c= 832020 J

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4 years ago

Which of these is an example of a physical change?

miv72 [106K]

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3 years ago

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