Answer:
1.86 s
Explanation:
Given the expression
h(t) = -16t²+ 64...................... Equation 1
Where h = height of the object, t = time it will take the object to hit the ground.
Given: h = 64 foot.
We have to concert from foot to meters
If 1 foot = 0.3048 meters
Then, 64 foot = 0.3048×64 = 19.51 meters.
We substitute the value of h into equation
119.51 = -16t²+64
-16t² = 199.51-64
-16t² = 55.51
t² = 55.51/-16
t² = 3.469
t = √3.469
t = 1.86 s.
Hence it will take the object 1.86 s to hit the ground.
Answer:
Potential energy
Explanation:
Potential energy is the energy stored within an object, due to the object's position, arrangement or state. Potential energy is one of the two main forms of energy, along with kinetic energy.
Since the total pressure of each gas is the sum of the partial pressures of all the individual gases, the vapor pressure of oxygen is 1.3 atm.
From Dalton's law of partial pressure, the total pressure is the sum of the individual partial pressures of the gases;
PT = PA + PB + PC + --------
Given that;
Vapor pressure of oxygen = 0.2 atm
Total pressure = 1.5 atm
Vapor pressure of oxygen = ?
Partial pressure of oxygen = 1.5 atm - 0.2 atm = 1.3 atm
The vapor pressure of oxygen is 1.3 atm.
Learn more: brainly.com/question/2510654
If the sphere is positively charged, the positive rod is repelled by the sphere while the negative rod is attracted by the sphere.
<h3>What is an electrical charge?</h3>
An electrical charge can be positive or negative. From the laws of electrostatics, unlike charges attract while like charges repel. As such the effect observed when the rods are individually brought near the sphere will decide the charge on the sphere.
If the sphere is neutral, there is no effect observed when each rod is brought near the sphere. If the sphere is positively charged, the positive rod is repelled by the sphere while the negative rod is attracted by the sphere.
Learn more about electrostatics: brainly.com/question/9774180
Answer:
<em>The velocity of the camera just before it hit the ground = 35.97 m/s.</em>
Explanation:
Velocity: This can be defined as the ratio of the displacement of a body to the time. Velocity is a vector quantity, and as such it can be represented both in magnitude and direction.
From the equation of motion,
v² = u² + 2gs ................ Equation 1
Where v = final velocity, u = initial velocity, g = acceleration due to gravity, s = distance.
Note: Before the velocity of the camera before it hits the ground = The final velocity of the camera.
<em>Given: u = 10.8 m/s, s = 60 m. g = 9.81 m/s.</em>
<em>Substituting into equation 1,</em>
<em>v² = 10.8² + 2(9.81)(60)</em>
<em>v² = 116.64+1177.2</em>
<em>v² = 1293.84 </em>
<em>v = √(1293.84)</em>
<em>v = 35.97 m/s.</em>
<em>Hence the velocity of the camera just before it hit the ground = 35.97 m/s.</em>
