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adell [148]
3 years ago
11

Is the following nuclear reaction balanced? Need answered ASAP!

Physics
2 answers:
elena55 [62]3 years ago
5 0

The correct answer would be yes

ycow [4]3 years ago
5 0

no is the answer. which is the answer to your question


You might be interested in
calculate the work done in kilo joules in lifting a mass of 20kg at steady velocity through a vertical height of 20m
bulgar [2K]

Answer:

\huge\boxed{\sf Work\ done = 4 kJ}

Explanation:

Since work done is in the form of potential energy, we will use the formula of potential energy here.

We know that,

<h3>P.E. = mgh </h3>

Where,

m = mass = 20 kg

g = acceleration due to gravity = 10 m/s²

h = vertical height = 20 m

So,

<h3>Work done = mgh</h3>

Work done = (20)(10)(20)

Work done = 4000 joules

Work done = 4 kJ

\rule[225]{225}{2}

5 0
2 years ago
HELP ASAP
Sladkaya [172]
Answer:
I think the answer is
C) iron nails are attracted towards all materials
8 0
2 years ago
Kepler's laws follow which law discovered by Sir Isaac Newton?
11111nata11111 [884]

B. Universal Gravitational Law

4 0
3 years ago
Read 2 more answers
The formation of a new substance shows that what change occurs
ycow [4]
A chemical change might also result in the formation of a precipitate, such as the appearance of a cloudy material when dissolved substances are mixed. Rotting, burning, cooking, and rusting are all further types of chemical changes because they produce substances that are entirely new chemical compounds.
7 0
3 years ago
A new ride being built at an amusement park includes a vertical drop of 71.6 meters. Starting from rest the ride vertically drop
AnnyKZ [126]

Answer:

We can conclude 2.3x10^7 J was converted to thermal energy

Explanation:

<u>Energy Conservation </u>

According to the law of conservation of energy, the total energy of an isolated system must be constant. If some kind of energy is 'lost', we know it was transformed into another type.

Let's check the conditions of the problem. The ride vertically drops a distance of 71.6 m starting from rest, and at the bottom of the drop, its speed is 10 m/s. Knowing the mass of the cart plus passengers is 3.5X10^4 kg, we compute the total energy at the top of the drop.

E=U+K

Where E is the total energy (which must be conserved) at the top of the drop, U is the gravitational potential energy and K is the kinetic energy. We use the equations for each:

U=m.g.h

\displaystyle K=\frac{mv^2}{2}

\displaystyle E=m.g.h+\frac{mv^2}{2}

At the top, the speed is 0, thus

\displaystyle E=m.g.h=(35000)(9.8)(71.6)=2.5X10^7\ J

Now we compute the 'total' energy at the bottom (quoted because we know there is some mechanical energy loss in the drop)

\displaystyle E'=m.g.h'+\frac{mv'^2}{2}

This time h'=0 and v=10 m/s, thus

\displaystyle E'=\frac{(35000)10^2}{2}=1.8x10^6\ J

The mechanical energy at the top and the bottom are not the same, thus we can know part of it was converted to heat or thermal energy. We compute the difference

2.5x10^7\ J-1.8x10^6\ J=2.3x10^7\ J

We can conclude 2.3x10^7 J was converted to thermal energy

4 0
3 years ago
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