Answer:
Amount of work done by Joanne = 80 joule
Explanation:
Given:
Displacement of ball = 2 meters
Force applied = 40 newtons
Find:
Amount of work done by Joanne
Computation;
Work done = Force applied x Displacement
Amount of work done by Joanne = Force applied x Displacement of ball
Amount of work done by Joanne = 40 x 2
Amount of work done by Joanne = 80 joule
Answer:
A is the answer
Explanation:
That's why it ranges from big to small.
Answer:
414.9 m
Explanation:
First, become familiar with the horizontal, and vertical vector components.
Vertical vector: Vy = V × sin (θ).
Horizontal vector: Vx = V × cos(θ).
Distance traveled = Velocity vector × time in the air.
Time in the air given Vy = 2 × Vy / g (in respect to the metric of the vector).
Range of the projectile = Vx² / g
Time in the air given Vx = (Vx + √(Vx)² + 2gh) / g.
Given a 28° angle with an initial velocity of 70m/s, we have enough information to calculate!
Vx = 70 m/s × cos(28°) ≈ 61.806 m/s
Vy = 70 m/s × sin(28°) ≈ 32.863 m/s
t = 2 × Vy / g
t = 2 × ≈32.863 / 9.8
t = ≈65.726 / 9.8
t ≈ 6.7 s
Distance traveled (horizontal) = Vx × t = 61.806 × 6.7 ≈ 414.9 m
Answer:
John
Explanation:
John Dalton is the scientist with the atomic model.
Answer:
f_2 = 436 Hz
Explanation:
Given:
- Frequency of the note played f_1 = 440 Hz
- Number of beats heard per second b = 4 Hz
Find:
What was the frequency of the mis-tuned A string?
Solution:
- The beat is the difference in frequency of the notes played and is given by the expression:
| f_1 - f_2 | = beats
- we heard 4 beats, so
| f_1 - f_2 | = 4
- Plug in the value: | 440 - f_2 | = 4
Hence, f_2 = 436 Hz
