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tino4ka555 [31]
3 years ago
13

2 resistors of resistance 1000 ohm and 2000 ohm are joined in series with a 100V supply. A voltmeter of internal resistance 4000

ohm is connected to measure the potential difference across 1000 ohm resistor. Calculate the reading shown by the voltmeter.
Physics
1 answer:
Vadim26 [7]3 years ago
5 0
<h2>The voltmeter reading will be 35.7 volt </h2>

Explanation:

The resistor 1000 ohm and 4000 ohm are connected in parallel .

Their combined resistance is supposed R₁

Thus \frac{1}{R_1} = \frac{1}{1000} + \frac{1}{4000}  

or R₁ = 800 ohm

Therefore the total resistance in circuit is = 2000 + 800 = 2800 ohm

Because these are in series .

We can find  current flowing through the circuit  I = \frac{V}{R} = \frac{100}{2800} = \frac{1}{28}

here R is total resistance .

The potential difference across 1000 ohm = \frac{1}{28} x 1000 = 35.7 volt

Thus voltmeter reading will be 35.7 volt

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