Appositives a force of 2 N to the left and 3 N to the right which is true of the Box motion

cyclohexanol is burned as a fuel, according to the following equation, how many moles of oxygen are needed to produce 13.7 mol o

lidiya [134]

The moles of oxygen that are needed to produce 13.7 moles of carbon dioxide is 21.17 moles of Oxygen

<u><em>calculation</em></u>

2 C₆H₁₂O + 17 O₂ → 12 CO₂ +12 H₂O

The moles of O₂ is determined using the mole ratio

that is for given equation above O₂ : Co₂ is 17 :12

therefore the moles of O ₂= 13.7 moles x 17/12 =21.17 moles

3 0

3 years ago

explain how to determine the number of atoms, cations, and anions in ionic compounds. use an example to explain.

Damm [24]

Answer:

use coefficients and subscripts to determine how many atoms are in a compound. If there is no subscript or coefficient, assume it is 1. If there is a coefficient, multiply it with the subscripts. For counting cations and anions, determine first which is the anion and cation (anion = nonmetal, cation = metal), then count the number of that ion.

Example:

NaCl

one atom of Na, one atom of Cl. Since Na is a metal, it is a cation. Cl is a nonmetal, so it is an anion.

2CaCl2

2 atoms of Ca, 4 atoms of Cl. There are 2 cations, since Na is a metal, and 4 anions since Cl is a nonmetal

8 0

2 years ago

A student prepares a 1.8 M aqueous solution of 4-chlorobutanoic acid (C2H CICO,H. Calculate the fraction of 4-chlorobutanoic aci

Kruka [31]

Answer:

Percentage dissociated = 0.41%

Explanation:

The chemical equation for the reaction is:

$C_3H_6ClCO_2H_{(aq)} \to C_3H_6ClCO_2^-_{(aq)}+ H^+_{(aq)}$

The ICE table is then shown as:

$C_3H_6ClCO_2H_{(aq)} \ \ \ \ \to \ \ \ \ C_3H_6ClCO_2^-_{(aq)} \ \ + \ \ \ \ H^+_{(aq)}$

Initial (M) 1.8 0 0

Change (M) - x + x + x

Equilibrium (M) (1.8 -x) x x

$K_a = \frac{[C_3H_6ClCO^-_2][H^+]}{[C_3H_6ClCO_2H]}$

where ;

$K_a = 3.02*10^{-5}$

$3.02*10^{-5} = \frac{(x)(x)}{(1.8-x)}$

Since the value for $K_a$ is infinitesimally small; then 1.8 - x ≅ 1.8

Then;

$3.02*10^{-5} *(1.8) = {(x)(x)}$

$5.436*10^{-5}= {(x^2)$

$x = \sqrt{5.436*10^{-5}}$

$x = 0.0073729 \\ \\ x = 7.3729*10^{-3} \ M$

Dissociated form of 4-chlorobutanoic acid = $C_3H_6ClCO_2^- = x= 7.3729*10^{-3} \ M$

Percentage dissociated = $\frac{C_3H_6ClCO^-_2}{C_3H_6ClCO_2H} *100$

Percentage dissociated = $\frac{7.3729*10^{-3}}{1.8 }*100$

Percentage dissociated = 0.4096

Percentage dissociated = 0.41% (to two significant digits)

3 0

3 years ago

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Find the % composition for each element in Zn(CIO3)2

bezimeni [28]

Zn = 28.15%

Cl = 30.53%

O = 41.32%

<h3>Further explanation</h3>

Given

Zn(CIO3)2 compound

Required

The % composition

Solution

Ar Zn = 65.38

Ar Cl = 35,453

Ar O = 15,999

MW Zn(CIO3)2 = 232.3

Zn = 65,38/232.3 x 100% = 28.15%

Cl = (2 x 35.453) / 232.3 x 100% = 30.53%

O = (6 x 15.999) / 232.3 x 100% = 41.32%

7 0

3 years ago

A carbon-carbon double bond has a greater bond energy than a carbon-carbon single bond. Because of the greater bond energy, a ca

Ronch [10]

<u>Answer:</u> Carbon-carbon double bond is stronger and shorter than the single bond.

<u>Explanation:</u>

It is given that carbon-carbon double bond has greater energy than the carbon-carbon single bond.

Bond energy is directly proportional to the bond strength, which means that the double bond will have greater strength than single bond and triple bond has the greatest strength of all the bonds.

$\text{Bond energy}\propto \text{Bond strength}$

Bond energy is inversely proportional to the bond length of the carbon-carbon bond. This means that more is the bond energy, shorter will be the bond and vice-versa.

$\text{Bond energy}\propto \frac{1}{\text{Bond Length}}$

Hence, carbon-carbon double bond is stronger and shorter than the single bond.

5 0

3 years ago

Read 2 more answers