Cesium is the biggest, atom wise.It has 55 protons.
C the products are on the right side of the arrow
Answer:
The plasmodial slime molds are the kind of protist that can live in groups in which different individuals perform different jobs. Some kinds of bacterial cell walls also have other functions.
The mass of the substance is the quantitative measure of the physical object. The mass of the sample must be reported as 3.5465 g. Thus, option e is correct.
<h3>What is mass?</h3>
The mass of the substance is the quantity of matter that the sample weighs and is reflected in grams or kilograms.
Given,
Mass of empty sample container = 12.00 g
Mass of sample + empty container = 15.5465 g
The mass of the sample will be given as,
mass of sample = (Mass of sample + empty container) - ( Mass of empty container)
= (15.5465 g - 12.00g)
=3.5465 g
Therefore, 3.5465 gm is the mass of the sample, and the correct option is e.
Your question is incomplete, but most probably your full question was, A label on an empty sample container reads 12.00 g. you add in a sample of a compound and the mass of the sample container obtaining 15.5465 g. what should the mass of the sample be reported as?
- 3.546 g
- 3.54 g
- 4 g
- 4.0 g
- 3.5465 g
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Explanation:
The given data is as follows.
= 9,
= ?
Z for hydrogen = 1
As we know that,
Energy (E) = 
where, h = planck's constant =
Js
c = speed of light =
m/s
= wavelength
According to Reydberg's equation, we will calculate the energy emitted by the photon as follows.
![\Delta E = -2.179 \times 10^{-18} J \times (Z)^{2}[\frac{1}{n^{2}_{2}} - \frac{1}{n^{2}_{1}}]](https://tex.z-dn.net/?f=%5CDelta%20E%20%3D%20-2.179%20%5Ctimes%2010%5E%7B-18%7D%20J%20%5Ctimes%20%28Z%29%5E%7B2%7D%5B%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B1%7D%7D%5D)
or,
= ![-2.179 \times 10^{-18} J \times (Z)^{2}[\frac{1}{n^{2}_{2}} - \frac{1}{n^{2}_{1}}]](https://tex.z-dn.net/?f=-2.179%20%5Ctimes%2010%5E%7B-18%7D%20J%20%5Ctimes%20%28Z%29%5E%7B2%7D%5B%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B1%7D%7D%5D)
Putting the given values into the above equation as follows.
= ![-2.179 \times 10^{-18} J \times (Z)^{2}[\frac{1}{n^{2}_{2}} - \frac{1}{n^{2}_{1}}]](https://tex.z-dn.net/?f=-2.179%20%5Ctimes%2010%5E%7B-18%7D%20J%20%5Ctimes%20%28Z%29%5E%7B2%7D%5B%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7Bn%5E%7B2%7D_%7B1%7D%7D%5D)
=
n = 2
Thus, we can conclude that the final level of the electron is 2.