Answer:
0.88g
Explanation:
The reaction equation:
2NaI + Cl₂ → 2NaCl + I₂
Given parameters:
Mass of Sodium iodide = 2.29g
Unknown:
Mass of NaCl = ?
Solution:
To solve this problem, we work from the known to the unknown.
First find the number of NaI from the mass given;
Number of moles =
Molar mass of NaI = 23 + 126.9 = 149.9g/mol
Now insert the parameters and solve;
Number of moles =
= 0.015mol
So;
From the balanced reaction equation;
2 moles of NaI produced 2 moles of NaCl
0.015mole of NaI will produce 0.015mole of NaCl
Therefore;
Mass = number of moles x molar mass
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
Now;
Mass of NaCl = 0.015 x 58.5 = 0.88g
Answer:
D: Atmospheric pressure is greater than vapor pressure,and water molecules escape from the solution into the air.
The atomic number is the numbers of protons
N(NaCl)=8 moles
M(NaCl)=A(Na)+A(Cl)
M(NaCl)=22.99+35.45=58.44 g/moles
m(NaCl)=n(NaCl)·M(NaCl)
m(NaCl)=8moles·58.44g/moles=467.52 g