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Ray Of Light [21]
3 years ago
12

Answer all questions on there plz 100 points come on

Mathematics
2 answers:
saw5 [17]3 years ago
3 0

this is the answer to question one

3:1:2 = 90:30:60

and the answer to the second one

Mkey [24]3 years ago
3 0

Answer: The answer to the cube one is 13 times 13 which gives u 169 and one of those is red so the ratio is 1 red cube to 168 black cubes or 1:168

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Can someone help me please ?
mafiozo [28]
25^(n-3)=5^(n+8)
Remember: 25=5²
Therefore:
5^[(n-3)²]=5^(n+8)
5^(2n-6)=5^(n+8)
Then:
2n-6=n+8
2n-n=8+6
n=14

Answer: n=14


7 0
3 years ago
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The cylindrical part grain silo is 10 meters tall and has a radius of 5 meters. What is the volume of grain that the cylindrical
ra1l [238]

Answer: 250π m³

Step-by-step explanation:

I took the quiz!!

8 0
2 years ago
The radius is 20. what's the length of arc AB?
AURORKA [14]

Answer:yyghvggft

Step-by-step explanation:

3 0
3 years ago
Find the commission on a $1,250 sale with a commission rate of 5%.
Nana76 [90]
Essentially, we must take 5% of $1250. When we drop the percent sign, we move the decimal 2 places to the left, giving .05. Then "of" means multiply. We take $1250 and multiply times .05, giving 
<span>$62..50 </span>

<span>Another way to do it is to take 10%, or $125. </span>
<span>Then 5% is half of that. Half of $125 is $62.50 We can do that by dividing $125 by 2. I did it in my head. Others might do it on paper. Still others might have a calculator handy and say $125 divided by 2 on the calculator. We should all get the same answer unless one person spaces out or is tired. It happens!</span>
5 0
3 years ago
Read 2 more answers
20 POINTS!!!
notka56 [123]

\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------

(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s

6 0
2 years ago
Read 2 more answers
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