Answer : The mass of NaCl required are 14.61 grams
Explanation : Given,
Molar mass of NaCl = 58.44 g/mole
Volume of solution = 500.00 mL
Molarity of NaCl = 0.5 M = 0.5 mole/L
Molarity : It is defined as the number of moles of solute present in 1 liter of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the mass of NaCl required are 14.61 grams
Answer:
Explanation:
BrO3- (aq) + Sb^3+ (aq) --------> Br^3- (aq) + Sb^5+ (aq) is an unbalanced equation and needs to be balanced
BrO3- (aq) → Br^3- (aq
to balance it water must be added to the right side and H⁺ be added to the left side
BrO₃⁻ + 6 H⁺ + 8e⁻ → Br³⁻ + 3 H₂ O
Sb³⁺ (aq) → Sb⁵⁺ + 2e⁻
multiply the second equation by 4
BrO₃⁻ + 6 H⁺ + 8e⁻ → Br³⁻ + 3 H₂ O
4Sb³⁺ → 4Sb⁵⁺ + 8 e⁻
add the two equation together and cancel the 8 e electrons on both side
BrO₃⁻ + 4Sb³⁺ + 6 H⁺ → Br³⁻ + 4Sb⁵⁺ + 3 H₂ O
number of mole of BrO₃⁻ = volume in liters × molarity = (29.9 / 1000) L × 0.120 M = 0.003588 moles
from the balanced equation of reaction;
one mole of BrO₃⁻ requires 4 moles of Sb³⁺
0.003588 moles of BrO₃⁻ will require = 0.003588 × 4 = 0.0144 moles of Sb³⁺
a) amount of antimony in grams in the sample = 0.0144 moles × 121.8 g ( molar mass of antimony) = 1.748 g
b ) percentage of antimony in the ore = 1.748 g / 6.33 g = 27.62 %
Answer:
The percent yield of the reaction is 82.5%
Explanation:
Let's work with moles to get the percent yield.
Mass / Molar mass =
652.5 g / 158.03 g/m = 4.13 moles
If the theoretical yield of the reaction is 5 moles but we only made 4.13 moles, the percent yield will be:
(Produced yield / Theoretical yield) . 100 =
(4.13 / 5) . 100 = 82.5 %
Explanation:
As it is given that solubility of water in diethyl ether is 1.468 %. This means that in 100 ml saturated solution water present is 1.468 ml.
Hence, amount of diethyl ether present will be calculated as follows.
(100ml - 1.468 ml)
= 98.532 ml
So, it means that 98.532 ml of diethyl ether can dissolve 1.468 ml of water.
Hence, 23 ml of diethyl ether can dissolve the amount of water will be calculated as follows.
Amount of water =
= 0.3427 ml
Now, when magnesium dissolves in water then the reaction will be as follows.
Molar mass of Mg = 24.305 g
Molar mass of = 18 g
Therefore, amount of magnesium present in 0.3427 ml of water is calculated as follows.
Amount of Mg =
= 0.462 g
Explanation:
Speed depends on your referential. Some chemical reactions can take only a fraction of a second while others take days.
Combustion is typically very fast. You can also try and look at lithium+water which is a dangerous, fast and exothermic reaction.