Answer:
The total atoms present in the chemical formula is 13
Explanation:
1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.
How to calculate number of atoms?
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
However, the number of moles of oxygen in glycine can be calculated using the following expression:
Molar mass of C₂H5O2N = 75.07g/mol
Mass of oxygen in glycine = 32g/mol
Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine
Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles
Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms
Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.
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We Know, Atomic number of Uranium = 92
Molar mass in given species = 233
Now, Molar mass = Number of Protons + Number of Neutrons
233 = 92 + x
x = 233 - 92
x = 141
So, your final answer is 141
Hope this helps!
Answer:
The density of air goes down as you get higher with altitude.
Explanation:
Less air is pushing down on the molecules below it as you go up. This means that it is not as compacted, another word for which is dense.
Answer: The ΔH of the reaction if 51.3 g of 
reacts with excess 
to yield 1387.6 kJ is 432.27kJ
Explanation:
To calculate the moles, we use the equation:
moles of
As is present in excess, is the limiting reagent as it limits the formation of product.
If 3.21 moles of methane releases heat = 1387.6 kJ
Thus 1 mole of methane release=
