Answer: As per the question, a ray of light is incident on a surface and it is partly reflected and refracted. The incident light is an unpolarised light. The reflected light is partially polarised.
If the angle of incidence becomes equal to the Brester angle (polarising angle), then the reflected light is completely plane polarised.
The time the truck must apply the given force to increase its speed to given value is 5 s.
The given parameters;
- <em>applied force, F = 600 N</em>
- <em>mass of the truck, m = 1,500 kg</em>
- <em>speed of the truck, v = 2 m/s</em>
The force applied to the truck is determined by Newton's second law of motion; <em>which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.</em>
F = ma
![F = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{1500 \times 2}{600} \\\\t = 5 \ s](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bmv%7D%7Bt%7D%20%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7Bmv%7D%7BF%7D%20%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B1500%20%5Ctimes%202%7D%7B600%7D%20%5C%5C%5C%5Ct%20%3D%205%20%5C%20s)
Thus, the time the truck must apply the given force to increase its speed to given value is 5 s.
Learn more here:brainly.com/question/1988795
Complete question:
A diver is 10 m below the surface of water. Calculate the pressure the fluid exerted on the diver. The acceleration of gravity is 9.8 m/s2 and the density of the water is 1000 kg/m3. Answer in units of Pa. Show your work.
Answer:
Tthe pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa
Explanation:
Given;
density of water, ρ = 1000 kg/m³
diver's position below the surface of the water, h = 10 m
acceleration due to gravity, g = 9.8 m/s²
Let the atmospheric pressure, P₀ = 101325 Pa
The pressure 10 m below the surface of the water is calculated as;
P = P₀ + ρgh
P = 101325 Pa + (1000 x 9.8 x 10)Pa
P = 199325 Pa
P = 1.99 x 10⁵ Pa.
Therefore, the pressure the fluid exerted on the diver is 1.99 x 10⁵ Pa
Answer:
His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. ... In reaction, a thrusting force is produced in the opposite direction.
Explanation:
Answer:
The drop time ball 1 is less than the drop time of ball 2. A further explanation is provided below.
Explanation:
The net force acting on the ball will be:
⇒ ![F_{net}=mg-F_r](https://tex.z-dn.net/?f=F_%7Bnet%7D%3Dmg-F_r)
Here,
F = Force
m = mass
g = acceleration
Now,
According to the Newton's 2nd law of motion, we get
⇒ ![F_{net} = ma](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20ma)
To find the value of "a", we have to substitute "
" in the above equation,
⇒ ![ma=mg-F_r](https://tex.z-dn.net/?f=ma%3Dmg-F_r)
⇒ ![a=g-\frac{F_r}{m}](https://tex.z-dn.net/?f=a%3Dg-%5Cfrac%7BF_r%7D%7Bm%7D)
We can see that, the acceleration is greater for the greater mass of less for the lesser mass. Thus the above is the appropriate solution.