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yulyashka [42]
4 years ago
7

Which element would not have similar properties with Calcium?

Chemistry
2 answers:
MakcuM [25]4 years ago
7 0
K potassium would be the answer
elena-14-01-66 [18.8K]4 years ago
5 0
Potassium would not have similar properties because it is the alkali metals, not alkali earth metals
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Type the correct answer in the box. Spell all words correctly. In which system are both energy and matter exchanged with the sur
Anna11 [10]

Answer:

open system

Explanation:

An open system is a system in which both energy and matter are exchanged with the surroundings.

4 0
3 years ago
The value of A for an atom containing 12 protons, 12 electrons and 16 neutrons is
Zepler [3.9K]

Answer: A = atomic number = 12

Explanation: A (atomic number) defines the chemical element. It is the numbervof protons or electrons. Neutron numbers may vary, produving isotopes of differing atomic mass. This isotope has atomic mass 28. The atomic number 12 = carbon. C28 does not really exist. If it could be produced it would be radioactive with an almost zero halflife.

3 0
3 years ago
How does sleeping help us maintain homeostasis?
hjlf

Answer:

Sleep homeostasis denotes a basic principle of sleep regulation. A sleep deficit elicits a compensatory increase in the intensity and duration of sleep, while excessive sleep reduces sleep propensity

Explanation:

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7 0
3 years ago
The combining of waves as they overlap is known as...
Inga [223]
The question to your answer would be either a or C
8 0
3 years ago
12.5 mL of 6.0 M KCl is diluted to make a 1.5 L solution. The molarity of the dilution solution is ___ M. (Round atomic masses t
horsena [70]

The molarity of the dilution solution is 0.050 M

<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

Dilution formula :

\tt M_1.V_1=M_2.V_2

M₁=6 M

V₁=12.5 ml

V₂=1.5 L=1500 ml

\tt 6\times 12.5=M_2\times 1500\\\\M_2=\dfrac{6\times 12.5}{1500}=0.05~M\\\\for~sig.fig\rightarrow 0.050~M

4 0
3 years ago
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