Answer:
The final temperature is:- 7428571463.57 °C
Explanation:
The expression for the calculation of heat is shown below as:-
Where,
is the heat absorbed/released
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of water = 1.75 mg = 0.00175 g ( 1 g = 0.001 mg)
Specific heat of water = 4.18 J/g°C
Initial temperature = 35 °C
Final temperature = x °C
kcal
Also, 1 kcal = 4.18 kJ = J
So, Q = J = 54340000 J
So,
Thus, the final temperature is:- 7428571463.57 °C
Conditions for rusting
• moisture
•oxygen
Prevention
•Painting
• Galvanisation
• Making Alloys
• greasing
Hope this helps you ;)(:
CuSO4 *5H20
In the formula of the hydrate, on the first place is the salt and on the second of water. so in ration on the first place should be salt also.
Answer:
Explanation:
According to the Law of Conservation of Mass, the mass of the products must equal the mass of the reactants.
- mass products = mass reactants
In this problem, the reaction is:
- The reactants are iron and oxygen. We know the mass of the iron sample is 10 grams.
- The product is ferric oxide. The mass of the ferric oxide sample is 18.2 grams.
We want to find how many grams of oxygen reacted. We have to get the oxygen by itself. 10 is being added to oxygen. The inverse of addition is subtraction. Subtract 10 from both sides of the equation.
<u>8.2 grams of oxygen </u>reacted with 10 grams of iron to form 18.2 grams of ferric oxide.