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2 years ago

What is the difference between an element, compound, and a mixture

Chemistry

1 answer:

cricket20 [7]2 years ago

3 0

Answer:

Element: Pure substance consisting of one type of atom. Compound: Pure substance consisting of two or more different atoms. Mixture: Two or more different substances not chemically combined.

Explanation:

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The area of a telescope lens is 7903 rnrn2 {a) What is the area in square feet (ft2)? (b) If it takes a technician 45 s to polis

LekaFEV [45]

Answer:

Area is 0.08504 $ft^{2}$ and $2.6\times 10^{3}s$ are needed for polishing

Explanation:

(a) ft is unit of F.P.S system whether mm is unit of M.K.S system.

According to unit conversion, $1mm=0.00328ft$

So, $1mm^{2}=(0.00328)^{2}ft^{2}=1.076\times 10^{-5}ft^{2}$

hence, $7903mm^{2}=7903\times 1.076\times 10^{-5}ft^{2}=0.08504ft^{2}$

So, area of telescope lens is 0.08504 $ft^{2}$

(b) $135mm^{2}$ are polished in 45s

So, $7903mm^{2}$ are polished in $\frac{45\times 7903}{135}s$ or $2.6\times 10^{3}s$

5 0

2 years ago

Classify each of these statements as always true, at; sometimes true, st; or never true, nt. 11. the rate at which a solute diss

photoshop1234 [79]

It is always true that the rate at which a solute dissolves can be increased by grinding. The smaller the solute the easier it will dissolve in the solvent, while other facts play into the rate at which a solute dissolves in a solvent, a major part of this is also how small the solute is. You can think of how rock salt is harder to dissolve in water compared to finely ground salt.

It is sometimes true that as the temperature of a solvent decreases, the solubility of a solute increase. The reason for this is that for liquids and solids as temperature increases the solubility increases but for gasses, as the temperature increases the solubility decreases.

It is always true that stirring a solute when adding it to a solvent should increase the rate of its dissolving. however, this will not increase the amount that is able to be dissolved in the solution.

It is never true that Henry's law states that the solubility of a gas in a liquid is a function of temperature. Henry's law is a gas law that was determined by William Henry in 1803. The law dictates that when in constant temperature the amount of gas that dissolves in a given volume of a liquid is proportional directly to the partial pressure of the gas at equilibrium with the desired liquid. In simpler terms, the solubility of the gas in a certain liquid is proportional to the partial pressure of the gas above the liquid.

It is always true that two liquids that dissolve in each other are miscible. Miscibility is described as the property of liquids and other substances to mix in all proportions and forming homogeneous solutions.

6 0

3 years ago

Energy is neither created or destroyed true or false

Dafna11 [192]

That statement is true.

-TTL

7 0

3 years ago

9. Thallium-208 has a half-life of 3.053 min. How long will it take for 120 g of it to decay

damaskus [11]

Answer:

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

Explanation:

Radioactive isotopes decay exponentially in time, the mass of the isotope ( $m(t)$ ), in grams, is described by the formula in time ( $t$ ), in minutes:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ (1)

Where:

$m_{o}$ - Initial mass of the isotope, in grams.

$\tau$ - Time constant, in minutes.

In addition, the time constant associated with the isotope decay can be described in terms of half-life ( $t_{1/2}$ ), in minutes:

$\tau = \frac{t_{1/2}}{\ln 2}$ (2)

If we know that $m(t) = 7.5\,g$ , $m_{o} = 120\,g$ and $t_{1/2} = 3.053\,min$ , then the time taken by the isotope is:

$\tau = \frac{t_{1/2}}{\ln 2}$

$\tau = \frac{3.053\,min}{\ln 2}$

$\tau \approx 4.405\,min$

$t = -\tau \cdot \ln \frac{m(t)}{m_{o}}$

$t = -(4.405\,min)\cdot \ln \left(\frac{7.5\,g}{120\,g} \right)$

$t \approx 12.213\,min$

12.213 minutes will be taken for 120 g-Thalium-208 to decay to 75 grams.

4 0

2 years ago

A quantity of gas has a volume if 400.0 ml when confined under a pressure of 600.0mm Hg. What will be the new volume of the gas

den301095 [7]

Answer:

1200 mL

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 400 mL.

Initial pressure (P1) = 600 mmHg.

Final volume (V2) =..?

Final pressure (P2) = 200 mmHg

Step 2:

Determination of the final volume i.e the new volume of the gas.

Considering the question given, we understood that the temperature is constant. Therefore the gas is obeying Boyle's law. Using the Boyle's law equation, the new volume is obtained as follow:

P1V1 = P2V2

600 x 400 = 200 x V2

Divide both side by 200

V2 = (600 x 400) /200

V2 = 1200 mL

Therefore, the new volume of the gas is 1200 mL.

3 0

2 years ago