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Montano1993 [528]
2 years ago
6

This is a graded Quiz and I need all of the answers to be right but I am not sure so I need help this is a 3.08 science Quiz and

it's do today. Thank you for the help
Question 1 (1 point)

True or False

Intrusive igneous rocks have fine-grained crystals.

Tue
False


Question 2 (1 point)

True or false

Igneous rocks are formed from cooling and hardening magma or lava.

True
False


Question 3 (1 point)

True or false

Metamorphic rocks are formed when sediments harden it to rocks.

True
False


Question 4 (1 point)

True or false

Lithification is the process of converting sediments into solid rock through compaction and cementation.

True
False


Question 6 (1 point)

What type of rock forms when heat and pressure change existing rocks WITHOUT melting them?


Metamorphic

Sedimentary

Igneous



Question 7 (1 point)

Once a metamorphic rock, always a metamorphic rock. cannot change from one type of rock to another

True
false


Question 8 (1 point)

The rock cycle has a definitive beginning and end

true
false


Question 9 (1 point)


Foliation occurs in sedimentary rocks

True
false


Some of the words are not spelled right and that's all my teachers fault i'm sorry.
Also if you are the first to answer and you answered all the of the questions and answered them right you will get marked brainly whatever it's called just please answer these all true fully and right and not just pick one for the points thank you bye
Chemistry
1 answer:
Setler79 [48]2 years ago
8 0

Answer:

1 true

Explanation:

bcz it is true

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2H2O = 2H2 + O2.

<h3><u>Explanation</u>:</h3>

Balancing equations is very essential because of the fact that it represents the stoichiometric quantities of the reactants needed to react to form the product. The ratio of the weights of reactant and product are also very well understood from this.

Here in this equation, the water is broken into hydrogen and oxygen. The balanced reaction is

2H2O = 2H2 + O2.

Two moles of water is broken down into 2 moles of hydrogen and one mole of oxygen.

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What happens to dissolving rate when you increase KE?
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If you mix 50mL of 0.1 M TRIS acid with 60 mL of0.2 M<br> TRIS base, what will be the resulting pH?
Katyanochek1 [597]

<u>Answer:</u> The pH of resulting solution is 8.7

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

  • <u>For TRIS acid:</u>

Molarity of TRIS acid solution = 0.1 M

Volume of solution = 50 mL

Putting values in above equation, we get:

0.1M=\frac{\text{Moles of TRIS acid}\times 1000}{50mL}\\\\\text{Moles of TRIS acid}=0.005mol

  • <u>For TRIS base:</u>

Molarity of TRIS base solution = 0.2 M

Volume of solution = 60 mL

Putting values in above equation, we get:

0.2M=\frac{\text{Moles of TRIS base}\times 1000}{60mL}\\\\\text{Moles of TRIS base}=0.012mol

Volume of solution = 50 + 60 = 110 mL = 0.11 L    (Conversion factor:  1 L = 1000 mL)

  • To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=pK_a+\log(\frac{[\text{TRIS base}]}{[\text{TRIS acid}]})

We are given:

pK_a = negative logarithm of acid dissociation constant of TRIS acid = 8.3

[\text{TRIS acid}]=\frac{0.005}{0.11}

[\text{TRIS base}]=\frac{0.012}{0.11}

pH = ?

Putting values in above equation, we get:

pH=8.3+\log(\frac{0.012/0.11}{0.005/0.11})\\\\pH=8.7

Hence, the pH of resulting solution is 8.7

6 0
3 years ago
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