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Step2247 [10]
2 years ago
8

Culinary arts HELP FAST 1. Most people don't often think about science and restaurants or the food industry as

Chemistry
1 answer:
Andrews [41]2 years ago
6 0

Answer:

i dont know

Explanation:

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if a 500.0-g block of metal absorbs 5,016J of heat when its temperature changes from 20.00 Celcius, what is the specific heat?
ZanzabumX [31]
Correction: The temperature change is from 20 °C to 30 °C.

Answer:
               Cp  =  1.0032 J.g⁻¹.°C⁻¹

Solution:

The equation used for this problem is as follow,

                                                  Q  =  m Cp ΔT   ----- (1)

Where;
            Q  =  Heat  =  5016 J

            m  =  mass  =  500 g

            Cp  =  Specific Heat Capacity  =  ??

            ΔT  =  Change in Temperature  =  30 °C  -  20 °C  =  10 °C

Solving eq. 1 for Cp,

                                 Cp  =  Q / m ΔT

Putting values,
                                 Cp  =  5016 J / (500 g × 10 °C)

                                 Cp  =  1.0032 J.g⁻¹.°C⁻¹
4 0
3 years ago
KCl is an ionic salt with a formula weight of 74.54 g/mole. A 1.417 M (mole/liter) KCl solution has a density of 1064.5 grams/li
xenn [34]

Answer:

Mass of the salt:  105.6g of KCl.

Mass water: 958.9g of water.

Molality: 1.478m.

Explanation:

<em>Mass of the salt:</em>

In 1L, there are 1.417 moles. In grams:

1.417 moles KCl * (74.54g / mol) = 105.6g of KCl

<em>Mass of the water:</em>

We can determine the mass of solution (Mass of water + mass KCl) by multiplication of the voluome (1L and density 1064.5g/L), thus:

1L * (1064.5g / L) = 1064.5g - Mass solution.

Mass water = 1064.5g - 105.6g = 958.9g of water

<em>Molality:</em>

Moles KCl = 1.417 moles KCl.

kg Water = 958.9g = 0.9589kg.

Molality = 1.417mol / 0.9589kg = 1.478m

3 0
3 years ago
How much water must be added to 6.0 M silver nitrate in order to make 500 mL of 1.2 M solution?
algol [13]

The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL

<u>Given data :</u>

Concentration of siilver nitrate ( M₁ ) = 6.0 M

volume of solution ( V₁ ) = 500 mL

Conc of solution ( M₂ )= 1.2 M

<h3>Determine the amount of water that must be added</h3>

we will apply the equation below

M₁V₁ = M₂V₂ ---- ( 1 )

where : V₂ = V₁ + water added  ---- ( 2 )

V₂ ( Final volume ) = ( M₁V₁ ) / M₂

                              = ( 6 * 500 ) / 1.2

                              = 2500 mL

Back to eqaution ( 2 )

2500 mL = 500 mL + added water

therefore ; added water = 2500 - 500

                                        = 2000 mL

Hence we can conclude that The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL.

Learn more about Volume : brainly.com/question/12410983

#SPJ1

7 0
2 years ago
This gas law works only if temperature is recorded in ———— units
Vsevolod [243]

Answer:

Kelvin

Explanation:

  • Gas laws re the laws that relates properties of gases such as pressure, temperature and volume at different conditions.
  • Gas laws includes, Boyle's law, Charles law, grahams law and pressure law among others.
  • Temperature is one of the quantity of gases explained by gas laws. For gas laws to work, temperature should always be in Kelvin. Therefore, when given temperature in degrees, it is converted to Kelvin by adding 273, that is °C + 273 = K.
8 0
2 years ago
Examples of electromagnetic wave
dlinn [17]

Answer:

Believe it or not our the light we see "visible light" is an example of electromagnetic wave. other examples include microwaves, radio waves, infrared, ultraviolet, x-rays, and gamma rays.

Explanation:

3 0
3 years ago
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