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olga2289 [7]
3 years ago
14

Arrange the following elements in order of decreasing atomic radius: Ba, Sn, S, Pb, and As. Rank elements from largest to smalle

st.
Chemistry
1 answer:
vodka [1.7K]3 years ago
8 0

Answer:

Ba>Sn>Pb>As>S

Explanation:

Hello,

In this case, we can write the atomic radius for the given elements:

r_{Ba}=268pm\\r_{Sn}=225pm\\r_{S}=100pm\\r_{Pb}=202pm\\r_{As}=185pm

In such a way, the required order is:

Ba>Sn>Pb>As>S

This is also in agreement as a periodic trend which states that the higher the period, the higher the radius.

Regards.

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Explain in terns of atomic structure why barium has a lower first ionization energy than magnesium.
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Barium has a greater radius than magnesium

Explanation:

Barium and magnesium are two elements which belong to the same group, group 2A. This means that the two elements have two valence electrons in their outer shell.

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Si agrega un ácido a una base, ¿qué pasará?
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3 years ago
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The reaction of 4.8g of sulfur and 5.4g aluminum yields 4.5g Al2S3. 3S+2AL--&gt;Al2S3 Determine the percent yield of Al2S3.
Goshia [24]

Answer:

59.9% is the percent yield for the 4.5 g of produced Al₂S₃

Explanation:

Let's determine the reaction:

3S  +  2Al  →  Al₂S₃

First of all, let's determine the limiting reactant. We need to convert the mass to moles:

4.8 g /32.06g/mol = 0.150 moles of S

5.4 g / 26.98 g/mol = 0.200 moles of Al

3 moles of S react to 2 moles of Al

Then, 0.150 moles of S may react to (0.150 . 2)/3 = 0.1 ,moles of Al

We have 0.200 moles and we only have 0.1. As we have excess of Al, this is the excess reactant. In conclussion, the limiting reagent is S.

2 moles of Al react to 3 moles of S

Then 0.2 moles of Al may react to (0.2 . 3) /2 = 0.3 moles of S. (We only have 0.150 moles)

Let's go to the product, 3 moles of S can produce 1 mol of Al₂S₃

Then 0.150 moles of S, may produce (0.150 . 1) /3 = 0.05 moles.

We convert moles to mass to determine the thoretical yield:

0.05 mol . 150.15g /mol =  7.50g

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% = (4.5g / 7.5g) . 100 = 59.9%

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