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olga2289 [7]
3 years ago
14

Arrange the following elements in order of decreasing atomic radius: Ba, Sn, S, Pb, and As. Rank elements from largest to smalle

st.
Chemistry
1 answer:
vodka [1.7K]3 years ago
8 0

Answer:

Ba>Sn>Pb>As>S

Explanation:

Hello,

In this case, we can write the atomic radius for the given elements:

r_{Ba}=268pm\\r_{Sn}=225pm\\r_{S}=100pm\\r_{Pb}=202pm\\r_{As}=185pm

In such a way, the required order is:

Ba>Sn>Pb>As>S

This is also in agreement as a periodic trend which states that the higher the period, the higher the radius.

Regards.

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Answer:

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Explanation:

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6 0
3 years ago
What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
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Answer:

34.28 L ( 1.5*22.4 L)

Explanation:

Calculation of the moles of aluminum as:-

Mass = 55 g

Molar mass of aluminum = 26.981539 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{55\ g}{26.981539\ g/mol}

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According to the reaction:-

4Al+3O_2\rightarrow 2Al_2O_3

4 moles of aluminum react with 3 moles of oxygen gas

1 mole of aluminum react with \frac{3}{4} moles of oxygen gas

2.0384 moles of aluminum react with \frac{3}{4}\times 2.0384 moles of oxygen gas

Moles of oxygen gas = 1.5288 moles

At STP,  

Pressure = 1 atm  

Temperature = 273.15 K

Using ideal gas equation as:

PV=nRT

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P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 1.5288 mol × 0.0821 L.atm/K.mol × 273.15 K

⇒V = 34.28 L ( 1.5*22.4 L)

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Answer:

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Explanation:

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Explanation:

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