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harina [27]
3 years ago
15

Uses of photosynthesis products what are the uses for the photosynthesis products

Chemistry
2 answers:
Aloiza [94]3 years ago
7 0
<h2><u>Question :-</u></h2>

What is photosynthesis?

<h3>____________________</h3>

<h2><u>Answer :-</u></h2>

The process by which green plants and some other organisms use sunlight to synthesize nutrients for their nourishment is called Photosynthesis.

<u>Some requirements of photosynthesis to take place :- </u>

  • Presence of carbon dioxide.

  • Presence of water.

  • In plants, in photosynthesis, require a green coloured pigment named 'Chlorophyll'.

  • Presence of Sunlight.

  • A temperature of 25°C to 40°C is needed.

<u>Result ( product ) of photosynthesis :-</u>

When the process of photosynthesis is completed, it releases Oxygen as a by-product.

<u>Chemical Equation for Photosynthesis :-</u>

\sf6CO_2 + 6H_2O    \binom{sunlight  \: and \: chorophyll}{ \rightarrow} C_6H _ {12} {O _6 + 6O_2} \uparrow

<h3>____________________</h3>

<h3><u>Note :-</u></h3>

Scroll from right to left to see the whole solution.

mario62 [17]3 years ago
3 0

Answer:

uses of photosynthesies:

Explanation:

In photosynthesis ENERGY from light is used to convert CARBONDIOXDE and water into glucose and oxygen for 6 carbon and 6 water molecules, 1 glucosed and 6 oxygen molecules are produced.

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U-238 has _____ protons and 146 neutrons
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U-238 
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Molar mass= protons + neutrons
This means that 238= 146 + protons
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Answer is 92
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A regular 3-d spatial arrangement of points that correspond to atom positions within a crystal is called_______?
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1 year ago
Some animals that live in extremely cold environments protect themselves from freezing by increasing the molality of certain che
lara [203]
  • Molality is defined as the number of moles of solute dissolved per 1000g(1kg) of solvent.
  • It is represented by m

\\ \sf \longmapsto m=\dfrac{Moles\:of\:solute}{Wt\:of\:solvent(in\:g)}\times 1000

8 0
3 years ago
The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl et
Alexxx [7]

<u>Answer:</u> The vapor pressure of solution is 459.17 mmHg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For testosterone:</u>

Given mass of testosterone = 7.752 g

Molar mass of testosterone = 288.4 g/mol

Putting values in equation 1, we get:

\text{Moles of testosterone}=\frac{7.752g}{288.4g/mol}=0.027mol

  • <u>For diethyl ether:</u>

Given mass of diethyl ether = 208.0 g

Molar mass of diethyl ether = 74.12 g/mol

Putting values in equation 1, we get:

\text{Moles of diethyl ether}=\frac{208.0g}{74.12g/mol}=2.81mol

Mole fraction of a substance is calculated by using the equation:

\chi_A=\frac{n_A}{n_A+n_B}

\chi_{\text{testosterone}}=\frac{n_{\text{testosterone}}}{n_{\text{testosterone}}+n_{\text{diethyl ether}}}

\chi_{\text{testosterone}}=\frac{0.027}{0.027+2.81}\\\\\chi_{\text{testosterone}}=0.0095

The formula for relative lowering of vapor pressure will be:

\frac{p^o-p_s}{p^o}=i\times \chi_{\text{solute}}

where,

p^o = vapor pressure of solvent (diethyl ether) = 463.57 mmHg

p^s = vapor pressure of the solution = ?

i = Van't Hoff factor = 1 (for non electrolytes)

\chi_{\text{solute}} = mole fraction of solute (testosterone) = 0.0095

Putting values in above equation, we get:

\frac{463.57-p^s}{463.57}=1\times 0.0095\\\\p^s=459.17mmHg

Hence, the vapor pressure of solution is 459.17 mmHg

7 0
3 years ago
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