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skad [1K]
3 years ago
10

A driver of a car enters a new 110 km/h speed zone on the highway. The driver begins to accelerate immediately and reaches 110 k

m/h after driving 500 m. if the original speeds was 80 km/hr, what was the driver’s rate of acceleration?
Physics
1 answer:
levacccp [35]3 years ago
3 0

Answer:

30Km/h

Explanation:

acceleration is the change of speed in a given time so when we substract the accelerations we can know how much the car goes per an hour

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Minchanka [31]

Answer:

C

Explanation:

8 0
3 years ago
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marishachu [46]

Answer:

the last one: weight force

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3 years ago
As you found out in the previous part, bernoulli's equation tells us that a fluid element that flows through a flow tube with de
8090 [49]
This causes the fluid to increase its speed. Bernoulli's principle tells us that an increase in the speed of a fluid happens at the same time with a reduction in pressure or a reduction in the fluid's potential energy. This necessitates that the amount of kinetic energy, potential energy and internal energy stays persistent.
8 0
3 years ago
A 100-n force has a horizontal component of 80 n and a vertical component of 60 n. the force is applied to a box which rests on
iragen [17]
<span>160 Joules

   For this problem, we can ignore the vertical component of the applied force and focus on only the horizontal component of 80 N and since work is defined as force over distance, let's multiply the force by the distance: 80 N * 2.0 m = 160 Nm = 160 kg*m^2/s^2 = 160 Joules.

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6 0
3 years ago
A mxiture of n2 and H2 has mole fraction of 0.4 and 0.6 respectively. Determine the density of the mixture at one bar and 0 c.
SOVA2 [1]

Answer:

The density of the mixture is 0.55kg/m^3

Explanation:

P = 1bar = 100kN/m^2, T = 0°C = 273K, n = 0.4+0.6 = 1mole

PV = nRT

V = nRT/P = 1×8.314×273/100 = 22.70m^3

Mass of N2 = 0.4×28 = 11.2kg

Mass of H2 = 0.6×2 = 1.2kg

Mass of mixture = 11.2 + 1.2 = 12.4kg

Density of mixture = mass/volume = 12.4/22.7 = 0.55kg/m^3

3 0
3 years ago
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