Row A: x = 3
y = 2x - 3
y = 2(3) - 3 = 3 This is correct
Row B: x = 5
y = 2x - 3
y = 2(5) - 3 = 7 This is correct
Row C: x = 7
y = 2x - 3
y = 2(7) - 3 = 11 this is correct
Row D: x = 10
y = 2x - 3
y = 2(10) - 3 = 17 THIS IS INCORRECT, SO ROW D
The answer for your question is B. 5
Answer:
Step-by-step explanation:
let x be part at 8%, y be part at 10% and z be part at 15%
(1) x+y+z=6300
the amount of money invested at 15% was $100 more than the amounts invested at 8% and 10% combined. so
(2) z=x+y+100
The total annual income from these investments was $766. so
0.08x+0.1y+0.15z=766 or
(3) 8x+10y+15z=76600
substitute (2) into (1)
x+y+x+y+100=6300
(4) 2x+2y=6200
substitute (2) inot (3)
8x+10y+15(x+y+100)=76600
(5) 23x+25y=75100
solving (4) n (5)
x=1200
y=1900
z=1200+1900+100=3200
Answer:
D
Step-by-step explanation:
On the way that this question is worded you would choose anything that would go up to 35 and anything below 35. Hope this helps you :)
Answer:
w=9
Step-by-step explanation:
