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Doss [256]
3 years ago
11

3st+2su-4sv factorised

Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0
The first step to factorising this expression, is finding what is common in each term.
The GCF of 3, 2 and -4 is 1 therefore we will not have a coefficient of the outside terms.
Then we have st, su and sv
s is common in all of them therefore we can take out s.

So far we have s(                )
Now for each term we must find what we multiply by s to reach it.
3st / s = 3t
2su / s = 2u
-4sv / s = -4v

Now just put these values inside the brackets.

s(3t + 2u - 4v)

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what is the decimal equivalent of the fraction? 7/12 enter your answer to the nearest thousandths in the box
Likurg_2 [28]
The answer is 0.583, and the 3 has a bar notation


Hope this helped

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4 0
2 years ago
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Stella bought a dinette set on sale for $725. The original price was $1,299. To the nearest tenth of a percent, what was the rat
kifflom [539]

Answer:

40%

Step-by-step explanation:

1299-725= 574

574/1299 x 100 = 44.19%

8 0
3 years ago
Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
The sum of an infinite geometric series is 1,280, while the first term of the series is 160. What is the common ratio of the ser
Arlecino [84]
The sum is 160/(1-r)=1280 where r is the common ratio,
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Inverting we get 1-r=1/8, r=7/8.
7 0
3 years ago
Please help me please
spayn [35]

Answer:

A. 34°

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] tanθ = opposite over adjacent
  • Inverse Trig

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

Angle θ = <em>x</em>

Opposite leg AC = 24

Adjacent leg CB = 35

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [Tangent]:                                                                    \displaystyle tanx^\circ = \frac{24}{35}
  2. Inverse Trig [Tangent]:                                                                                     \displaystyle x^\circ = tan^{-1}(\frac{24}{35})
  3. Evaluate:                                                                                                           \displaystyle x = 34.439^\circ
  4. Round:                                                                                                               \displaystyle x \approx 34^\circ
4 0
2 years ago
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