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drek231 [11]
2 years ago
11

1CO₂ (g) + 1C (s) → 2CO (g) Keq =

Chemistry
1 answer:
Stells [14]2 years ago
5 0

Answer:

the equation is balanced

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Chemist lectures about the following definition for acids and bases.
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Read 2 more answers
Consider the following redox equation Mn(OH)2(s) + MnO4 –(aq)  MnO42 –(aq) (basic solution) When the equation is balanced with
inysia [295]

Answer : The balanced chemical equation is,

2MnO_4^-(aq)+Mn(OH)_2(s)+4OH^-(aq)\rightarrow 3MnO_4^{2-}(aq)+2H_2O(l)

The coefficient for OH^- is, 4 and on reactant side of the equation OH^-(aq) is present.

Explanation :

Rules for the balanced chemical equation in basic solution are :

  • First we have to write into the two half-reactions.
  • Now balance the main atoms in the reaction.
  • Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
  • If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
  • If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion (OH^-) at that side where the less number of hydrogen are present.
  • Now balance the charge.

The half reactions in the basic solution are :

Reduction : Mn(OH)_2(s)+1e^-\rightarrow MnO_4^{2-}(aq) ......(1)

Oxidation : MnO_4^-(aq)+4OH^-(aq)\rightarrow MnO_4^{2-}(aq)+2H_2O(l)+2e^-.....(2)

Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

2MnO_4^-(aq)+Mn(OH)_2(s)+4OH^-(aq)\rightarrow 3MnO_4^{2-}(aq)+2H_2O(l)

Thus, the coefficient for OH^- is, 4 and on reactant side of the equation OH^-(aq) is present.

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3 years ago
The atomic number of an atom is always equal to the total number of
kobusy [5.1K]
Protons in the nucleus
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