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andrew11 [14]
3 years ago
11

N discussing engines, the ratio of output work to input work expressed as a percentage is called

Physics
1 answer:
djyliett [7]3 years ago
5 0

The ration of output work to input work expressed as a percentage is called <u>Efficiency</u>.

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Why did the “yielders” conform in Asch’s experiment?
svet-max [94.6K]

Answer:

Asch's experiment showed that about 75% of people were "yielders" who conformed and 25% were "independent" who didn't conform. Asch concludes that people ignored reality and gave an incorrect answer in order to follow the rest of the group.

4 0
2 years ago
How does charging by conduction work?
anzhelika [568]

Answer:

During charging by conduction, both objects acquire the same type of charge. If a negative object is used to charge a neutral object, then both objects become charged negatively. ... In this case, electrons are transferred from the neutral object to the positively charged rod and the sphere becomes charged positively.

6 0
3 years ago
11. A student lifts a 25 kg mass a vertical distance of 1.6 m in a time of 2.0 seconds.
goldenfox [79]

Answer:

a) 245 N

b) 392 J

c) 196 W

Explanation:

a) Force needed to lift the 25 kg object is the same as the weight of the object:

Force= m * g = 25kg * 9.8 \frac{m}{s^2} = 245 N

b) Work is the force exerted times the distance moved:

Work = F * d = 245N * 1.6 m = 392 Joules = 392 J

c) The power exerted is the quotient of the work done over the amount of time it took to move the object:

4 0
3 years ago
A kite 40 ft above the ground moves horizontally at a constant speed of 10 ft/s, with a child, holding the ball of kite string,
Lorico [155]

Answer:

 v = 27.28 m /s, θ = 63.9º

Explanation:

For this exercise we can approximate the movement to a projectile launch, let's analyze the situation.

* We must find the horizontal speed, for this we will find the descent time and the horizontal distance

* We look for the vertical speed

At the highest point the speed is horizontal

Let's find the time it takes for the kite to reach the ground

             y = y₀ + v_{oy} t - ½ g t²

             0 =y₀ + 0 -1/2 gt²

             t = \sqrt{ \frac{2y_o}{g} }

             t = √(2 40/32)

             t = 2.5 s

to find the horizontal velocity we must know the horizontal distance, let's use trigonometry

          sin θ = y / l

          θ = sin⁻¹1 y / l

          θ = sin⁻¹ 40/50

          θ = 53.1º

therefore the horizontal distance is

          x = l cos 53.1

          x = 50cos 53.1

          x = 30 m

let's use the equation

          x = v₀ₓ t

          v₀ₓ = x / t

          v₀ₓ = 30 / 2.5

          v₀ₓ = 12 m / s

we look for the vertical component of the velocity

          v_y = v_{oy} - g t

          v_y = 0 - g t

          v_y = - 9.8 2.5

          v_y = -24.5 m / s

the negative sign indicates that the speed is directed downwards, because it is the arrival point, as they indicate that there is no friction, the exit speed is the same, worse with the opposite sign

We already have the two components of the velocity, let's use the Pythagorean theorem to find the modulus

          v = \sqrt{v_x^2 + v_y^2}

          v = \sqrt{12^2 + 24.5^2}

          v = 27.28 m /s

we use trigonometry for the angle

          tan θ = v_y / vₓ

          θ = tan⁻¹ v_y / vₓ

          θ = tan⁻¹ 24.5 / 12

          θ = 63.9º

4 0
3 years ago
Which factors affect the gravitational force between objects? Check all that apply. difference in speed of objects direction of
zaharov [31]
Only the masses of the objects and the distance between them. Nothing else affects the gravitational forces. Not even a concrete, steel, and Kryptonite wall between them.
7 0
3 years ago
Read 2 more answers
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