How much thermal energy (q) is required to heat 15.2g of a metal (specific heat=0.397J/C) from 21.0C to 40.3C? Show steps please
1 answer:
You might be interested in
Answer : It takes less amount of heat to metal 1.0 Kg of ice.
Solution :
The process involved in this problem are :
Now we have to calculate the amount of heat released or absorbed in both processes.
<u>For process 1 :</u>
where,
= amount of heat absorbed = ?
m = mass of water or ice = 1.0 Kg
= enthalpy change for fusion =
Now put all the given values in , we get:
<u>For process 2 :</u>
where,
= amount of heat absorbed = ?
m = mass of water = 1.0 Kg
= specific heat of liquid water =
= initial temperature =
= final temperature =
Now put all the given values in , we get:
From this we conclude that, that means it takes less amount of heat to metal 1.0 Kg of ice.
Hence, the it takes less amount of heat to metal 1.0 Kg of ice.