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Fofino [41]
3 years ago
14

A person who controls access to the decision maker is called a(n)

Chemistry
1 answer:
damaskus [11]3 years ago
6 0

Answer:

Wdym?

Explanation:

I don't understand this question

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Why is the atomic weight of carbon reported as 12.011 in the table of elements and the periodic table in the front inside cover
Oduvanchick [21]
The atomic weight reported in the periodic table of elements for Carbon is the average weight of all the known isotopes of Carbon occurring naturally. There are 3: Carbon-12, Carbon-13 and Carbon-14. The numbers represent the mass numbers, or the sum of neutrons and protons in the nucleus. Each of the individual masses are multiplied with their individual percentage abundances. Then, when you add them up, it will yield the average atomic weight equal to 12.011 amu or grams/mole C.
5 0
3 years ago
Water freezes at _____. <br> A. 273°C<br> B. -273°C <br> C. 273 K<br> D. -273 K
BartSMP [9]
Correct answer is A
6 0
3 years ago
If a substance has a high hydronium concentration, the substance has a ____ pH.
aalyn [17]

Answer: low pH

Hydronium is H^+ and acids give hydronium ions to water solution.

PH = -log H^+ concentration. The higher the concentration, the lower pH value

4 0
3 years ago
How many moles of aspartame are present in 4.50 mg of aspartame?
Alekssandra [29.7K]

Answer:- 1.53*10^-^5mol .

Solution:- Aspartame is a artificial sweetener with molecular formula C_1_4H_1_8N_2O_5 and it's molecular mass is  294.3 gram per mol.

We have been given with 4.50 mg of aspartame and asked to calculate the moles. For mass to moles conversion we divide the given mass in grams by molar mass.

Since, the mass is given in mg, we need to convert it to g first.

1 mg = 0.001 g

So, 4.50mg(\frac{0.001g}{1mg})

= 0.00450 g

Now  let's calculate the moles on dividing the grams by molar mass as:

0.00450g(\frac{1mol}{294.3g})

= 1.53*10^-^5mol

Hence, 1.53*10^-^5mol are present in 4.50 mg of aspartame.

4 0
4 years ago
How can you identify a chloride from an iodide solution using the silver nitrate and sodium thiosulfate test?
scoundrel [369]
For the silver nitrate test, the solution is added first with nitric acid. This test is to determine halide ions. When silver nitrate is added to the solution, the color of the precipitate would indicate the identity of the ion. For chloride ions, the precipitate is white.

For the sodium thiosulfate test, chlorine is treated with Ki solution which turns brown. When it is titrated with sodium thiosulfate solution, the brown turns yellow upon which, starch is added. It forms a complex which appears as dark blue. Upon adding more titrant, it reaches the endpoint where the blue turns colorless.
7 0
4 years ago
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