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ElenaW [278]
3 years ago
12

Can You Tell? Pepsinogen is released in the stomach. Why can't it digest stomach walls?

Chemistry
1 answer:
miv72 [106K]3 years ago
5 0

Answer:

Specific cells within the gastric lining, known as chief cells, release pepsin in an inactive form, or zymogen form, called pepsinogen. By doing so, the stomach prevents the auto-digestion of protective proteins in the lining of the digestive tract.

Explanation:

Make sure to edit so you don't get copy-writed

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The body uses atoms in different ways to accomplish different tasks. For example, one portion of the body's calcium supply stren
Nikolay [14]

Answer:

The correct option is;

c. the bone contains calcium salts, which are less reactive than the calcium ions found in the blood.

Explanation:

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99 %  of the calcium in the human body are found in the bones while the remaining 1 % circulates in the blood as ions

The bones of the vertebrate are made up of calcium salts such as calcium carbonate, calcium phosphate and calcium fluoride.

3 0
3 years ago
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3 years ago
What pressure is exerted by 932.3 g of CH4 in a 0.560 L steel container at 136.2 K?
Roman55 [17]
Molar mass CH4 = 16.0 g/mol

* number of moles:

932.3 / 16 => 58.26875 moles

T = 136.2 K

V = 0.560 L

P = ?

R = 0.082

Use the clapeyron equation:

P x V = n x R x T

P x 0.560 =  58.26875 x 0.082 x 136.2

P x 0.560 = 650.76

P = 650.76 / 0.560

P = 1162.07 atm
5 0
3 years ago
What three tests must all theories pass to be considered a "proven" theory?
VladimirAG [237]

 In order to become a scientific theory the three categories that it must pass are the following: 


1) Can the phenomena be recreated in a laboratory setting? 


2) Can variables be changed, yet still result in like observations? 


3) Is the phenomena truly natural or was it the result of a man-made force enacting upon it?

7 0
3 years ago
Consider this reaction: 2al(s) + 3 cucl2(aq) → 2alcl3(aq) + 3 cu(s) if the concentration of cucl2 drops from 1.000 m to 0.655 m
kirza4 [7]
The average rate of reaction over a given interval can be calculated by taking the difference of concentration on a particular given reactant, and dividing it by the total time. In this case, (1.00 M - 0.655 M)/30 s = 0.0115 M/s, or 0.0115 mol/L-s, and this is the final rate of reaction.
8 0
3 years ago
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