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Lilit [14]
3 years ago
5

In the game of backgammon, you get to double how much you move if you roll “doubles" on two dice (that is: 1 and 1, 2 and 2, 3 a

nd 3, etc.). The next three questions concern this situation. 23. What is the probability of rolling doubles on any one roll?
(a) 1/6

(b) 1/12

(c) 1/36

(d) 5/36

(e) 1/2
Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0
*11* 12 13 14 15 16
21 *22* 23 24 25 26
31 32 *33* 34 35 36
41 42 43 *44* 45 46
51 52 53 54 *55* 56
61 62 63 64 65 *66*
(36 combos)

6/36 or 1/6 probability or rolling doubles.
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If a person puts 1 cent in a piggy bank on the first day, 2 cents on the second day, 3 cents on the third day, and so forth, how
cluponka [151]
This is an arithmetic sequence with the common difference being 1

and if u have 1 cent on day 1 and 2 cents on day 2....then on day 40, u would have 40 cents....but we need the sum of all the days..

the sum of an arithmetic sequence can be found using the formula :
sn = n(a1 + an) / 2
n = number of terms = 40
a1 = first term = 1
an = last term = 40

now we sub
s(40) = 40(1 + 40) / 2
s(40) = 40(41)/2
s(40) = 1640/2
s(40) = 820.....820 cents = $ 8.20 <== the sum
4 0
3 years ago
Two boys decided to buy a computer. The second boy had 5 6 of the money the first had. The first boy had 7 8 of the price of the
sdas [7]

Answer: The price for the computer = $1152

Step-by-step explanation:

Let the first boy = F

Let the second boy = S

Let the price of computer = C

The second boy had 5/ 6 of the money the first had. I.e

S = 5/6 F

Then F = 6/5S ......(1)

The first boy had 7 /8 of the price of the computer. That is

F = 7/8C ....... (2)

Substitute F in (1) into (2)

6/5S = 7/8C

S = 5/6 × 7/8C

S = 35/48C ......(3)

Together they had $696.00 more than they need to pay. That is

F + S = C + 696 ........ (4)

Substitute equation 2 and 3 into 4

7/8C + 35/48C = C + 696

0.875C + 0.729C = C + 696

0.604C = 696

C = 696/0.604

C = 1152 dollars

Therefore, the price for the computer = $1152

7 0
3 years ago
Read 2 more answers
Which is the side length of a cube with a volume of 1331 m3?
suter [353]
Let's remember the equation for the volume of a cube:
V= x^3 where x is the length of one side
Since a cube has equal length for length, width, and height.

Now, use what you're given
V= 1331

And put that in terms of x
x^3 = 1331

Now solve for x!
x= cube root (1331)

Think about it! cube root of 1331 * cube root of 1331 * cube root of 1331... will equal 1331 m^3!

Hope this helps
8 0
3 years ago
Patrick subtracted 4,832-2,322 and got 2,510.is hus difference reasonable?explain
notka56 [123]
Yes, patrick's answer is reasonable because that is the difference of 4832 and 2232. 
Hope this helped! :D
5 0
3 years ago
Y=x^(2) -2x - 3 and y = x - 3
Oliga [24]

Answer:

(0, -3) and (3, 0)

Explanation:

1st equation: y = x² -2x - 3

2nd equation : y = x - 3

Using substitution method:

x² -2x - 3 = x - 3            <em>exchange sides</em>

x² - 2x - x - 3 + 3 = 0    <em>simplify</em>

x² - 3x = 0   <em>                 take common factor</em>

x(x - 3) = 0                    <em>simplify</em>

x = 0, 3

Solve for y:

when x is 0, y = x - 3 = 0 - 3 = -3

when x is 3, y = x - 3 = 3 - 3 = 0

5 0
2 years ago
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