Answer:
0.23 g
Explanation:
From the question given above, the following data were obtained:
Mass of solution = 20.3 g
Percentage by mass of KCl = 1.14%
Mass of KCl =?
The mass of KCl in the solution can be obtained as follow:
Percentage by mass = mass of solute / mass of solution × 100
1.14% = mass of KCl / 20.3
Cross multiply
Mass of KCl = 1.14% × 20.3
Mass of KCl = 1.14/100 × 20.3
Mass of KCl = 0.0114 × 20.3
Mass of KCl = 0.23 g
Therefore, the mass of KCl in the solution is 0.23 g
Hey there mate ;)!,
Given : 100°C
To convert to Kelvin scale unit,
Add the Celsius unit with 273.
→ (100+273) K
→<em><u> </u></em><em><u>373 </u></em><em><u>K</u></em>
<em>Therefore</em><em> </em><em>the </em><em>answer</em><em> is</em><em> </em><u>373 Kelvin</u><em> </em><em>or </em><u>373 </u><u>K.</u>
<em>By </em><em>Benjemin</em> ☺️
Answer:
The final temperature of water is 54.5 °C.
Explanation:
Given data:
Energy transferred = 65 Kj
Mass of water = 450 g
Initial temperature = T1 = 20 °C
Final temperature= T2 = ?
Solution:
First of all we will convert the heat in Kj to joule.
1 Kj = 1000 j
65× 1000 = 65000 j
specific heat of water is 4.186 J /g. °C
Formula:
q = m × c × ΔT
ΔT = T2 - T1
Now we will put the values in Formula.
65000 j = 450 g × 4.186 J /g. °C × (T2 - 20°C )
65000 j = 1883.7 j /°C × (T2 - 20°C )
65000 j/ 1883.7 j /°C = T2 - 20°C
34.51 °C = T2 - 20°C
34.51 °C + 20 °C = T2
T2 = 54.5 °C
