Answer:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O
Explanation:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 1NaC₂H₃O₂
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂
(on the reactant side there are two molecules of C₂H₃O₂ and 2 atoms of Na, so in order to balance that we put the coefficient 2 on NAC₂H₃O₂)
So the final product is
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂
Answer:
The equilibrium constant for CO now
= 0.212 M
For H₂O
= 0.212 M
For CO₂ = x = 0.2880 M
For H₂ = x = 0.2880 M
Explanation:
The chemical equation for the reaction is:
CO(g) + H2O(g) ⇌ CO2(g) + H2(g)
The ICE Table for this reaction can be represented as follows:
CO(g) + H2O(g) ⇌ CO2(g) + H2(g)
Initial 0.5 0.5 - -
Change -x -x + x + x
Equilibrium 0.5 -x 0.5 - x
The equilibrium constant![K_c = \dfrac{[x][x]}{[0.5-x][0.5-x]}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cdfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.5-x%5D%5B0.5-x%5D%7D)
![K_c = \dfrac{[x]^2}{[0.5-x]^2}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cdfrac%7B%5Bx%5D%5E2%7D%7B%5B0.5-x%5D%5E2%7D)
where; 



1.3583 (0.5-x) = x
0.67915 - 1.3583x = x
0.67915 = x + 1.3583x
0.67915 = 2.3583x
x = 0.67915/2.3583
x = 0.2880
The equilibrium constant for CO now = 0.5 - x
= 0.5 - 0.2880
= 0.212 M
For H₂O = 0.5 - x
= 0.5 - 0.2880
= 0.212 M
For CO₂ = x = 0.2880 M
For H₂ = x = 0.2880 M
The way the air moves affects the weather, because winds move heat and cold temperatures as well as moisture from one place to another, transporting conditions from one geographical zone to another. The way winds pass each other, and the direction they move, also affects what weather a region will see on any given day.
Answer:
NaCl = 58.44g/mol
Explanation:
Na = 22.99/58.44 × 100 = 39.33%
Cl = 35.45/58.44 × 100 = 60.66%