Calculate the standard potential, e°, for this reaction from its equilibrium constant at 298 k. 6.47 x 10^5
1 answer:
The working equation for this is written below: E° = 0.0592logK/n So, we have to know the value of n first which represents the number of moles electron in the reaction. We cannot answer this because we are not given with the reaction. However, just suppose the reaction is: Cu⁺ + 2e⁻ --> Cu Then, n=2. Continuing, E° = 0.0592log(6.47×10⁵)/2 =<em> 0.172 V</em>
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The correct answer is D 4.29x10^24
Mass of Oxygen required : 24 grams
<h3>Further explanation</h3>
Given
3 moles of H
1.5 moles of O
3 moles of H₂O
Required
Mass of O
Solution
Reaction
2H₂ + O₂ ⇒ 2H₂O
Mass of Oxygen for 1.5 moles of O :
= mol x Ar O
= 1.5 moles x 16 g/mol
= 24 grams
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