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Tju [1.3M]
4 years ago
8

1. A 500-g block is placed on a level, frictionless surface and attached to an ideal spring. At t = 0 the block moves through th

e equilibrium position with speed vo in the –x direction, as shown below. At t =  sec, the block reaches its maximum displacement of 40 cm to the left of equilibrium. a. Determine the value of each of the following quantities. Show all work. • period: • spring constant: b. Using x(t) = A cos(t + o) as the solution to the differential equation of motion: i. Determine the form of the function v(t) that represents the velocity of the block. ii. Evaluate all constant parameters (A, , and o) so as to completely describe both the position and velocity of the block as functions of time. c. Consider the following statement about the situation described above. "It takes the first  seconds for the block to travel 40 cm, so the initial speed vo can be found by dividing 40 cm by  seconds." Do you agree or disagree with this statement? If so, explain why you agree. If not, explain why you disagree and calculate the initial speed vo of the block.
Physics
1 answer:
Thepotemich [5.8K]4 years ago
6 0

Answer:

Pls refer to attached handwritten document for calculation and detailed answer

Explanation:

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3 years ago
2. The components of vector A are given as follows:
Stella [2.4K]

Answer:

50 degree.

Explanation:

Given that the components of vector A are given as follows: Ax = 5.6 Ay = -4.7

The angle between vector A and B in the positive direction of x-axis will be achieved by using the formula:

Tan Ø = Ay/Ax

Substitute Ay and Ax into the formula above.

Tan Ø = -4.7 / 5.6

Tan Ø = -0.839

Ø = tan^-1(-0. 839)

Ø = - 40 degree

Therefore, the angle between vector A and B positive direction of x-axis will be

90 - 40 = 50 degree.

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Read 2 more answers
3. Two cyclists that are 500 m apart start biking toward each other. They bike at speeds of 6 and
Veronika [31]

Answer:

A) 50 seconds

B) 200 m

Explanation:

They are 500 metres apart.

And one of the bike loves at 6 m/s while the other loves at 4 m/s.

A) Let distance of the 6 m/s bike before they meet be x.

Thus, time = x/6

Since time = distance/speed

For the second bike at 4 m/s, his distance covered before they meet will be 500 - x

Thus, time = (500 - x)/4

Now they will meet each other at the same time. Thus;

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Cross multiply to get;

4x = 3000 - 6x

6x + 4x = 3000

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Thus, time will be;

t = 300/6

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Thus; distance = 500 - 300 = 200 m

4 0
3 years ago
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