<h3><u>Answer;</u></h3>
<em>By adding the amplitude of the two waves </em>
<h3><u>Explanation;</u></h3>
- <em><u>Wave is a transmission of a disturbance from one point to another. </u></em>Transmission of waves involves transport of energy from one point called the source to another.
- <em><u>A characteristic of wave in which two waves meet each other is called an interference. </u></em>When interference occurs it may either be constructive or destructive. When two waves are in sync with each other and occupy the same place at the same time is called constructive interference. <em><u>The amplitude of the resulting wave is the sum of the two original waves. For constructive interference the amplitude is normally larger than the original.</u></em>
Answer:the maximum Hall voltage across the strip= 0.00168 V.
Explanation:
The Hall Voltage is calculated using
Vh= B x v x w
Where
B is the magnitude of the magnetic field, 5.6 T
v is the speed/ velocity of the strip, = 25 cm/s to m/s becomes 25/100=0.25m/s
and w is the width of the strip= 1.2 mm to meters becomes 1.2 mm /1000= 0.0012m
Solving
Vh= 5.6T x 0.25m/s x 0.0012m
=0.00168T.m²/s
=0.00168Wb/s
=0.00168V
Therefore, the maximum Hall voltage across the strip=0.00168V
Answer:
hello your question is incomplete below is the missing part
Ex = 0
Ey = 
Explanation:
Attached below is a detailed solution showing the integration of the expression dEx and dEy from ∅ = 0 to ∅ =π
Ex = 0
Ey = 