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ryzh [129]
3 years ago
6

A sample of Xe takes 75 seconds to effuse out of a container. An unknown gas takes 37 seconds to effuse out of the identical con

tainer under identical conditions. What is the most likely identity of the unknown gas?
a. Br2
b. He
c. O2
d. Kr
Chemistry
2 answers:
Sergio [31]3 years ago
4 0

Answer:

The Answer is (c)

Explanation:

Rashid [163]3 years ago
3 0

Answer:

The molar mass of B is 32.0 g/mol

The unknown gas might be O2 (option C)

Explanation:

Step 1: Data given

A sample of Xe takes 75 seconds to effuse out of a container.

An unknown gas takes 37 seconds to effuse out of the identical container

Molar mass Xe = 131.3 g/mol

Step 2:

Rate A / rate B = √ (MB/MA)

rate = amount / time

The equation includes rate, but you are given times. Since rate is amount/time, we have to invert that side of the equation.

Time B/Time A = √(MB/MA)

⇒with time B = the time the unknown gas needed to effuse  = 37 seconds

⇒with time A = the time needed Xe needed to effuse = 75 seconds

⇒with MB = the molar mass of the unknown gas = TO BE DETERMINED

⇒ with MA = the molar mass of Xe = 131.3

37/75 = √ (MB/131.3)

MB = 32

The molar mass of B is 32.0 g/mol

The unknown gas might be O2

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Answer:

Le Chatelier's principle can be applied in explaining the results

Explanation:

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Hence, when the color of the solution was more like that of the control, the reaction would shift towards the left. Similarly, when the color was more like it was towards the reactant, the reaction would shift towards the right.

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4 0
3 years ago
The size (radius) of an oxygen molecule is about 2.0 ×10−10m. Make a rough estimate of the pressure at which the finite volume o
belka [17]

Answer:

Explanation:

We can calculate the volume  of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

volume=33.40×10⁻³⁰m³

Volume of oxygen molecule=33.40×10⁻³⁰m³

we know the ideal gas equation as:

PV=nRT

k=R/Na

R=k×Na

PV=n×k×Na×T

n×Na=N

PV=Nkt

p is pressure of gas

v is volume  of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the  formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

p=12.39×10⁷Pascal

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3 years ago
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The alcohol on board is cognac 2
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Dry air (0% humidity) is approximately 78% N2, 21% O2, and 1% Ar by moles. Calculate the molar mass and density of dry air at 0
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7 0
3 years ago
What volume will 0.405 g of krypton gas occupy at STP?
Rufina [12.5K]

Answer:

The answer to your question is V = 0.108 L or 108 ml

Explanation:

Data

Volume = ?

mass = 0.405 g

Temperature = 273°K

Pressure = 1 atm

Process

1.- Convert mass of Kr to moles

                  83.8 g of Kr -------------------- 1 mol

                     0.405 g     -------------------  x

                     x = (0.405 x 1) / 83.8

                     x = 0.0048 moles

2.- Use the Ideal gas law to solve this problem

                   PV = nRT

- Solve for V

                      V = nRT / P

- Substitution

                      V = (0.0048)(0.082)(273) / 1

- Simplification

                       V = 0.108 / 1

- Result

                       V = 0.108 L

8 0
3 years ago
Read 2 more answers
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