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frutty [35]
3 years ago
7

ich of the following is not accurate when describing solids? A. The amount of pressure exerted by a solid is solely dependent on

its mass. B. Molecules in solids are closer together than molecules in liquids. C. Solids with many air pockets are good insulators. D. Solids are better conductors of heat than liquids
Physics
1 answer:
Dafna11 [192]3 years ago
5 0
The amount of solid does not affect how you are describing the solid so a is the answer
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A crate is acted upon by a net force of 100N. An acceleration of 5.0 m/s^2 results. What is the rate of the crate?
andreev551 [17]
Is there any other information given? I don't think you can solve this without a time
6 0
3 years ago
Help please! this is physics !
KATRIN_1 [288]

Answer:

4. The choose b. 0.000355

Ans; 3.55× 10-⁴ = 0.000355

5. The choose C. 80600

Ans; 8.06 ×10⁴= 806×10² = 80600

I hope I helped you^_^

4 0
3 years ago
Read 2 more answers
A police car with its 300-Hz siren is moving toward a warehouse at 30 m/s, intending to crash through the door. The sound bounce
Lady bird [3.3K]

Answer: The frequency heard will be f = 275.675Hz

Explanation: When an object emitting sound is moving, it occurs a phenomenon called Doppler shift or Doppler effect. What happens is that the sound gets higher when the moving object comes closer the observer and becomes lower after it passes, This change is due to the quantity of waves that passes through an area in an unit of time.

The formula to calculate the Doppler effect is as follows

f = (\frac{c}{c+Vs}) · f₀

f is the observed frequency;

c is the speed of sound;

Vs is velocity of the source;

f₀ is the emitted frequency of source;

Substituting and calculating,

f = \frac{340}{340+30} · 300

f = 275.675 Hz

Thus, the frequency heard by the police officer is 275.675Hz.

8 0
3 years ago
Which memory disorder is a common illness on television and films
Alenkinab [10]
amnesia is the most common illness used in tv an films
5 0
3 years ago
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A 110-g bullet is fired from a rifle having a barrel 0.636 m long. Choose the origin to be at the location where the bullet begi
astraxan [27]
<span>Data:
mass =  110-g bullet
d = 0.636 m
Force = 13500 + 11000x - 25750x^2, newtons.

a) Work, W

W = ∫( F* )(dx) =∫[13500+ 11000x - 25750x^2] (dx) =

W =  13500x + 5500x^2 - 8583.33 x^3 ] from 0 to 0.636  =

W = 8602.6 joule

b) x= 1.02 m

</span><span><span>W =  13500x + 5500x^2 - 8583.33 x^3 ] from</span> 0 to 1.02

W = 10383.5

c) %

[W in b / W in a] = 10383.5 / 8602.6 = 1.21 => W in b is 21% more than work in a.


</span>
7 0
3 years ago
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