Answer:
given , v = 300 km/hr; distance d = 1500 km; then time t = d/v = 1500/300 = 5 hrs
Explanation:
Answer:
a) equal 1, b) less than 1
Explanation:
a) the electric force is given by
Fe = q E
The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative
Proton
Fp = qE
Electron
Fe = - q E
Fp / Fe = -1
If we do not take into account the sign the relationship is equal to one (1)
b) to calculate the force we use Newton's second law
F = ma
qE = m a
a = q E / m
The mass of the proton much greater than the mass of the electron
ap = q E /
ae = - q E /
ap / ae = /
= /1600 =1/1600
It is much smaller than 1
1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity
Answer:
Gravitational potential energy to kinetic energy
Explanation:
In this case you have a case about conservation of energy.
When the mass is released and allowed to fall, its energy is completely gravitational potential energy with a value of U = mgh. m is the mass, g is the gravitational constant and h is the height to the floor from the mass.
While the mass is falling down part of its potential energy converts to kinetic energy of value K=1/2mv^2, because the mass has been acquiring more and more velocity.
Thus, the kinetic energy is increasing while the potential energy is decreasing.
When the mass is just above the floor (the moment just before the mass hits the floor) all its potential energy has been converted to kinetic energy.
Then, you have that the kinetic energy of the mass when the mass is just above the floor, is equal to the potential energy when the mass is at height of h. That is:
This is how the law of conservation of energy is fulfilled.
Answer:
Explanation:
The computation of acceleration of the particle down the slope is shown below:-
data provided in the question
Particle of mass = 1.3 kg i,e sliding down
Inclined = 30 to the horizontal
based on the above information
Force is given by
............ 1
and sliding force is given by
=
Hence, the acceleration of the particle down the slope is 4.9 m/sec^2