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Alex Ar [27]
3 years ago
13

What colors form the spectrum of visible light

Physics
1 answer:
Law Incorporation [45]3 years ago
3 0
Red, orange, yellow, green, blue, indigo, violet :)
You might be interested in
How many atoms are present in 3 molecules of chromium
iren2701 [21]
Answer:

1,8066 x 1024 atoms

Explanation:

1 mole of chromium contains 6,022 x 1023 atoms

so

3 moles of chromium contains 3 times as many atoms

3 x 6,022 x 1023 = 1,8 066 x 1024

5 0
3 years ago
What unit can be used to measure the mass of a grain of salt
Anna007 [38]

milligrams

Explanation:

The best unit to measure the mass of a grain of salt is the milligram.

This is about; a thousandth of a gram.

  A grain of salt is a very small particle size that can still be visible with the eye.

It has a very low and small mass.

For substances like this, we use the milligram:

             1000milligram  = 1g

learn more:

Mass brainly.com/question/4736384

#learnwithBrainly

           

5 0
2 years ago
In the most common isotope of Hydrogen the nucleus is made out of a single proton. When this Hydrogen atom is neutral, a single
FinnZ [79.3K]

Answer:

The ratio of electric force to the gravitational force is 2.27\times 10^{39}

Explanation:

It is given that,

Distance between electron and proton, r=4.53\ A=4.53\times 10^{-10}\ m

Electric force is given by :

F_e=k\dfrac{q_1q_2}{r^2}

Gravitational force is given by :

F_g=G\dfrac{m_1m_2}{r^2}

Where

m_1 is mass of electron, m_1=9.1\times 10^{-31}\ kg

m_2 is mass of proton, m_2=1.67\times 10^{-27}\ kg

q_1 is charge on electron, q_1=-1.6\times 10^{-19}\ kg

q_2 is charge on proton, q_2=1.6\times 10^{-19}\ kg

\dfrac{F_e}{F_g}=\dfrac{kq_1q_2}{Gm_1m_2}

\dfrac{F_e}{F_g}=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{6.67\times 10^{-11}\times 9.1\times 10^{-31}\times 1.67\times 10^{-27}}

\dfrac{F_e}{F_g}=2.27\times 10^{39}

So, the ratio of electric force to the gravitational force is 2.27\times 10^{39}. Hence, this is the required solution.

3 0
3 years ago
How can you keep sound out of a room
GREYUIT [131]
To keep<span> noise from entering your space, look for </span>sound<span> blockers</span>
8 0
3 years ago
Ch 31 HW Problem 31.63 10 of 15 Constants In an L-R-C series circuit, the source has a voltage amplitude of 116 V , R = 77.0 Ω ,
Degger [83]

Answer:

a. I = 0.76 A

b. Z = 150.74

c. RL₁ = 34.41  ,  RL₂ = 602.58

d. RL₂ = 602.58

Explanation:

V₁ = 116 V , R₁ = 77.0 Ω , Vc = 364 V ,  Rc = 473 Ω

a.

Using law of Ohm

V = I * R

I = Vc / Rc =  364 V / 473 Ω

I = 0.76 A

b.

The impedance of the circuit in this case the resistance, capacitance and inductor

V = I * Z

Z = V / I

Z = 116 v / 0.76 A

Z = 150.74

c.

The reactance of the inductor can be find using

Z² = R² + (RL² - Rc²)

Solve to RL'

RL = Rc (+ / -) √ ( Z² - R²)

RL = 473 (+ / -)  √ 150.74² 77.0²

RL = 473 (+ / -)  (129.58)

RL₁ = 34.41  ,  RL₂ = 602.58

d.

The higher value have the less angular frequency  

RL₂ = 602.58

ω = 1 / √L*C

ω = 1 / √ 602.58 * 473

f = 285.02 Hz

6 0
3 years ago
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