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garik1379 [7]
3 years ago
13

The balanced equation for the reaction of ammonia and oxygen is the following. 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) The stand

ard molar entropies for the products and reactants are listed below. Calculate the change in standard molar entropy for this reaction at 298.0 K and standard pressure, in J/mol·K. (Enter your answer to the tenths place. Include the sign of the value in your answer.)
Chemistry
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

ΔS° = 180.5 J/mol.K

Explanation:

Let's consider the following reaction.

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)

The standard molar entropy of the reaction (ΔS°) can be calculated using the following expression.

ΔS° = ∑np × S°p - ∑nr × S°r

where,

ni are the moles of reactants and products

S°i are the standard molar entropies of reactants and products

ΔS° = 4 mol × S°(NO(g)) + 6 × S°(H₂O(g)) - 4 mol × S°(NH₃(g)) - 5 mol × S°(O₂(g))

ΔS° = 4 mol × 210.8 J/K.mol + 6 × 188.8 j/K.mol - 4 mol × 192.5 J/K.mol - 5 mol × 205.1 J/K.mol

ΔS° = 180.5 J/K

This is the change in the entropy per mole of reaction.

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This equation shows a ____ refer to this summary equation of photosynthesis to complete the sentences about chemical bonds and r
coldgirl [10]

The balanced chemical equation representing the process of photosynthesis is:

6 CO_{2} +12H_{2}O-->C_{6}H_{12}O_{6}+6O_{2}

The reactants in the process of photosynthesis are CO_{2}and HH_{2}O and the products of the reaction are glucose C_{6}H_{12}O_{6} and oxygen O_{2}. Oxygen is the nonpolar covalent gas which is released in the process of photosynthesis. The reactant CO_{2} is a nonpolar covalent gas while the other reactant waterH_{2}O has polar covalent O-H bonds.

In the balanced chemical equation, the number of each type of element must be equal on both sides of the reaction.

6 0
3 years ago
Explain why BH3 is trigonal planar and NH3 is trigonal pyramidal.
Troyanec [42]

Answer:o It is important to realise that mixing will be small unless there are electrons in the 4a1 LUMO, this is why NH3 is pyramidal while BH3 is planar! ... This mixing is very strong and stabilises the 3a1 MO substantially and hence NH3 is trigonal pyramidal and not planar.

Explanation:

3 0
3 years ago
I need help with part B . please
myrzilka [38]
So it's good to map out what you know you have and work from there:
We have two liter measurements and one mole measurement, and we need to find the moles.

For this problem, think of it this way: 46 liters of gas = 1.4 moles.
If one side changes, the other has to as well (if the liters decrease, the moles decrease. if the liters increase, so do the moles.) What you can do is put this into a fraction:

  <span><u>1.4 moles</u></span>
      46 L   <span> </span>

if we know that each liter of gas is equal to x amount of moles, we know that 11.5 liters equals some amount of moles. You can put this into a fraction too, and make it equal to the other fraction:

   <span><u>1.4 moles</u></span> = <u>x moles</u> 
         46 L         11.5 L

Then get your calculator out and do some algebra.

11.5 * (1.4/46) = x

The answer should come out to be: 0.35 moles
8 0
3 years ago
At 100°C, Kp = 60.6 for the reaction2NOBr(g) ⇄ 2NO(g) + Br₂(g) In a given experiment, 0.10 atm of each component is placed in a
Mariana [72]

The system is not at equilibrium.

The reaction will proceed to the right to attain the equilibrium.

Let's consider the following reaction.

2 NOBr(g) ⇌ 2 NO(g) + Br₂(g)

The pressure equilibrium constant (Kp) is 60.6. To determine if the system is at equilibrium when the pressure of each component is 1.75 atm, we have to calculate the reaction quotient (Q) and compare it with Kp.

Q = [NO]².[Br₂] / [NOBr]²

Q = (1.75)².(1.75) / (1.75)²

Q = 1.75

Since Q ≠ Kp, the system is not at equilibrium.

Since Q < Kp, the reaction will proceed to the right to attain the equilibrium.

To know more about equilibrium.

brainly.com/question/517289

#SPJ4

6 0
1 year ago
A: moving away from<br><br> B: moving towards<br><br> C: sliding past
iren [92.7K]

Answer:

B.moving towards each other

7 0
3 years ago
Read 2 more answers
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