All categories

3 years ago

Convert 1.25 atm to kPa

Chemistry

1 answer:

eduard3 years ago

8 0

Answer:

126.6562

Explanation:

You might be interested in

Question 2

natulia [17]

Explanation:

de Broglie wavelength= h/mv

v=h/m x de Broglie wavelength

v= (6.626× 10^-34)/ (2347× 1.27 × 10^-38)

v= 22.229 m/s(according to Google scientific calculator)

am sorry I don't hv a calculator at hand

3 0

3 years ago

Which statement is true about real gases with the correct reason:

LenKa [72]

There are 2 possible answers here : b and d.

The Ideal Gas Equation is : PV = nRT

Here, when pressure is increased and temperature is lowered, the volume of the molecules will substantially decrease, which means it has deviated from ideal behavior.

4 0

2 years ago

Read 2 more answers

Match the sentences with the steps of the scientific method.

Harrizon [31]

Answer: use your brain

Explanation:

I have one

6 0

3 years ago

Initial temperature of metal =

Evgesh-ka [11]

Answer:

the correct answers is 100 22.7 and 24.6

Explanation:

did it on edgunity

4 0

3 years ago

Read 2 more answers

Calculate the wavelength, in nanometers, of the spectral line produced when an electron in a hydrogen atom undergoes the transit

Lapatulllka [165]

Answer: The wavelength of spectral line is 656 nm

Explanation:

To calculate the wavelength of light, we use Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2} \right )$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $1.097\times 10^7m^{-1}$

$n_f$ = Final energy level = 2

$n_i$ = Initial energy level = 3

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.524\times 10^6m^{-1}}=6.56\times 10^{-7}m$

Converting this into nanometers, we use the conversion factor:

$1m=10^9nm$

So, $6.56\times 10^{-7}m\times (\frac{10^9nm}{1m})=656nm$

Hence, the wavelength of spectral line is 656 nm

6 0

3 years ago