Answer :
(A) The number of moles of
ions per liter is, 0.1 moles/L
(B) The number of molecules of
ion is, 
(C) The pH of the solution will be, 4
<u>Solution for part A :</u>
First we have to calculate the pOH of the solution.
As we know that,

Now we have to calculate the moles of
ion per liter.
![pOH=-\log [OH^-]\\\\1=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D%5C%5C%5C%5C1%3D-%5Clog%20%5BOH%5E-%5D)
![[OH^-]=0.1moles/L](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.1moles%2FL)
<u>Solution for part B :</u>
First we have to calculate the
ion concentration.
![pH=-\log [H^+]\\\\13=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D%5C%5C%5C%5C13%3D-%5Clog%20%5BH%5E%2B%5D)
![[H^+]=10^{-13}moles/L](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D10%5E%7B-13%7Dmoles%2FL)
Now we have to calculate the number of molecules of
ion
As, 1 mole contains
number of molecules of
ion
So,
moles contains
number of molecules of
ion
<u>Solution for part C :</u>
![pH=-\log [H^+]\\\\pH=-\log (1\times 10^{-4})](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D%5C%5C%5C%5CpH%3D-%5Clog%20%281%5Ctimes%2010%5E%7B-4%7D%29)

Answer:
(215 torr)(51 mL)=("x" torr)(18,500 mL) x = O.593 torr
Answer:
56.0 g
Explanation:
Calculation of the moles of
as:-
Mass = 85.0 g
Molar mass of
= 162.2 g/mol
The formula for the calculation of moles is shown below:
Thus,

According to the reaction:-

1 mole of
on reaction forms 1 mole of
Also,
0.52404 mole of
on reaction forms 0.52404 mole of
Moles of
= 0.52404 moles
Molar mass of
= 106.867 g/mol
Mass = Moles*Molar mass =
= 56.0 g
Answer:
See Explanation
Explanation:
When a salt is dissolved in water, the solution could be acidic, basic or neutral depending on the nature of acid and base from which the salt was formed.
When a salt is formed from a strong acid and a weak base, the salt solution is acidic.
For instance, NH4Cl is a salt formed from NH3 which is a weak base and HCl which is a strong acid. The salt hydrolyses as follows;
NH4^+(aq) + H2O(l) ------> H3O^+(aq) + NH3(aq)
Hence an acidic solution is formed.
7 protons , 7 neutrons , 2,5 electrons.