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earnstyle [38]
3 years ago
5

The refracting telescope at the Yerkes Observatory has a 1.00-m diameter objective lens of focal length 20.0 m. Assume it is use

d with an eyepiece of focal length 1.90 cm. (a) Determine the magnification of Mars as seen through this telescope.
Physics
2 answers:
dangina [55]3 years ago
8 0

Magnification = (focal length of the objective) / (focal length of the eyepiece)

                     =    (20.0 m)  /  (1.9 cm)

                     =      (2,000 cm)  /  (1.9 cm)

                     =        1,053  (rounded)
igomit [66]3 years ago
7 0
Angular magnifiction=m= \frac{ f_{0} }{ f_{e} }
f_{0}==focal length of object lens=20m
f_{e}=focal length of eye lens=1.90 m
so magnification=m=20/1.9=?
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Explanation :

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We know that the power dissipated is given by :

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I=\dfrac{P}{V}

I=\dfrac{0.064\ W}{3.6\ V}

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or

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3 0
3 years ago
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Particle 1 and particle 2 have masses of m1 = 2.2 × 10-8 kg and m2 = 4.8 × 10-8 kg, but they carry the same charge q. The two pa
Lorico [155]

Answer:r_2=11.81 cm

Explanation:

Given

m_1=2.2\times 10^{-8} kg

m_2=4.8\times 10^{-8} kg

same charge on both masses

potential Energy due to Magnetic Field =Kinetic Energy of Particle

qV=\frac{mv^2}{2}

v=\sqrt{\frac{2qV}{m}}

and we know

Force due to magnetic field will Provide centripetal Force

qvB=\frac{mv^2}{r}

B=\frac{\sqrt{\frac{2Vm}{q}}}{r}

and B is equal for both particles

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4 0
3 years ago
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Vera_Pavlovna [14]

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3 years ago
What is the compound oc2 called?
MAXImum [283]
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3 years ago
A rock is dropped from a height of 3,245 m. If we ignore air resistance, how fast will it be travelling after it falls for 3.4 s
Marta_Voda [28]

Answer:

<u>954.4m/s</u>

Explanation:

For a free falling object,it has constant acceleration and a changing velocity.

By using the velocity-time formula, the velocity can be obtained.

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From,

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That js the answer I got. Hope it's right.

3 0
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